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Anuta_ua [19.1K]
3 years ago
7

A balloon is filled with helium at a pressure of 2.4 x 105 Pa. The balloon is at a

Physics
1 answer:
garri49 [273]3 years ago
5 0
1)
p = 2.4 * 10^5 Pa
T = 18° C + 273.15 = 291.15 k
r = 0.25 m => V = [4/3]π(r^3) = [4/3]π(0.25m)^3 = 0.06545 m^3 = 65.45 L

Use ideal gas equation: pV = nRT => n = pV / RT = [2.4*10^5 Pa * 0.06545 m^3] / [8.31 J/k*mol * 291.15k] = 6.492 mol

Avogadro number = 1 mol = 6.022 * 10^23 atoms

Number of atoms = 6.492 mol * 6.022 *10^23 atom/mol = 39.097 * 10^23 atoms = 3.91 * 10^24 atoms

2) Double atoms => double volume

V2 / V1 = r2 ^3 / r1/3

2 = r2 ^3 / r1 ^3 => r2 ^3 = 2* r1 ^3

r2 = [∛2]r1

The factor is ∛2
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V- voltage

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R- resistance

V= I×R

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What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unch
Alenkinab [10]

Answer:

Potential difference and charge will also increase.

Explanation:

Asking that :

What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unchanged?

The charge is directly proportional to area of the plate. That is, increase in area of the plate of a capacitor will lead to the increase in the charges between the plates.

And since charge is also proportional to the magnitude of potential difference between the plates from the definition of capacitance of a capacitor which says that:

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3 years ago
A 78−kg skier is sliding down a ski slope at a constant velocity. The slope makes an angle of 21° above the horizontal direction
Feliz [49]

Answer:

274N 0.41

Explanation:

As he is sliding down in a constant speed then the force that accelerates him (weight) and the force that slows his down (friction) are equal.

then

<em>friction=mass x gravity x sin(21)</em>

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8 0
3 years ago
A motorcycle together with its Rider with 150 kg how much work is needed to set its movement at 15 metre per second.​
AVprozaik [17]

Answer:

W = 16875 J

Explanation:

We have,

Mass of a motorcycle together with its rider is 150 kg

It is required to find the work is needed to set its movement at 15 metre per second. The work done is given by :

W=\dfrac{1}{2}mv^2

Plugging all the values in above formula such that :

W=\dfrac{1}{2}\times 150\times (15)^2\\\\W=16875\ J

So, the work of 16875 J is needed.

5 0
3 years ago
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