1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zanzabum
3 years ago
9

According to the Arrhenius definitions of acids and bases, choose the acids from the list of acids and bases. Check all that app

ly.
HBr

Sr(OH)2

HClO

H2S

LiOH
Chemistry
1 answer:
ANEK [815]3 years ago
8 0

Answer:

The answers are:

  • HBr
  • HClO
  • H2S

You might be interested in
We can tell when a chemical reaction occurs by looking
gregori [183]
10. ¿Con qué soñaba la autora cuando era niña? ¿Qué espera hoy?
11. ¿Cómo describe ella su identidad? ¿Cómo se define?
12. ¿Por qué escribe Esmeralda Santiago? ¿Qué quiere expresar a sus lectores?
8 0
3 years ago
Write a set of rules for naming a binary molecular compound.
lys-0071 [83]

Answer:

Rule 1: Drop mono for the first element. Rule 2: Drop all prefixes if the first element is H. Rule 3: Drop the second o in mono prior to a vowel. Rule 4: Drop the a in prefixes ending in a prior to a vowel.

7 0
3 years ago
A 15.0 mL solution of Sr(OH)2 is neutralized with 38.5 mL of 0.350 M
Darya [45]

Answer:

Molarity of Sr(OH)₂  = 0.47 M

Explanation:

Given data:

Volume of Sr(OH)₂ = 15.0 mL

Volume of HCl = 38.5 mL (0.0385 L)

Molarity of HCl = 0.350 M

Concentration/Molarity of Sr(OH)₂  = ?

Solution:

Chemical equation:

Sr(OH)₂ + 2HCl     →      SrCl₂ +2H₂O

Number of moles of HCl:

Molarity = number of moles/ volume in L

0.350 M = number of moles/0.0385 L

Number of moles = 0.350 mol/L× 0.0385 L

Number of moles = 0.0135 mol

Now we will compare the moles of HCl with Sr(OH)₂.

                    HCl       :     Sr(OH)₂

                      2         :         1

                   0.0135   :      1/2×0.0135 = 0.007 mol

Molarity/concentration of Sr(OH)₂:

Molarity = number of moles / volume in L

Molarity = 0.007 mol /0.015 L

Molarity = 0.47 M

7 0
3 years ago
If your lawn is 21.0 ft wide and 20.0 ft long, and each square foot of lawn accumulates 1350 new snow flakes every minute. How m
GaryK [48]
<span>First we can calculate the area of the rectangular lawn using the formula:
Area = Width x Length = 21 ft x 20 ft = 420 square feet
       
And the total number of snow flakes per minute on the entire lawn is:
   
(1350 snowflakes per minute per square foot) x (420 square feet) = 567,000 snowflakes per minute
       
In one hour (or 60 minutes) we get a total of:
   
(567,000 snowflakes per minute) x (60 minutes / 1 hour) = 34,020,000 snowflakes
       
The total mass of which would be:
   
34,020,000 snowflakes x 1.60 mg = 54,432,000 mg = 54.432 kg (as 1 kg = 1,000,000 mg).
       
So 54.432 kg of snow accumulates every hour on the lawn.</span>
7 0
3 years ago
NEEEEEEEEEEEEEEEEED HELP
lakkis [162]
<h3> <u>Answer</u></h3>

4. loses 2 electrons

<h3><u>EXPLANATION</u></h3>

Mg²+ has 10 electrons while Mg has 12 electrons.

7 0
3 years ago
Other questions:
  • Which items in this image are electrically conductive? Check all that apply.
    9·2 answers
  • HELP ASAP! GIVING BRAINLIEST!!<br><br> How could you give a pendulum more energy?
    6·1 answer
  • A graph of 1/[A]t vs. time will give you a straight line if the reaction is which order?
    15·1 answer
  • What is the molar mass of calcium sulfate (caso4):?
    14·1 answer
  • I need help on number 2&amp;3
    5·2 answers
  • If you rub a balloon on a piece of fabric or carpeting and then hold it against your head, your hair can stand on end. Why?
    15·1 answer
  • An object's velocity can be described by its acceleration and direction.<br><br> True<br> False
    12·1 answer
  • Please someone help me with this!!
    7·2 answers
  • Oxidation unit test
    11·1 answer
  • An object is accelerated from rest to a speed of 50m/s in 10 seconds. The acceleration of the object is?
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!