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Answer:
18.84 g of silver.
Explanation:
We'll begin by calculating the number atoms present in 5.59 g of sulphur. This can be obtained as follow:
From Avogadro's hypothesis,
1 mole of sulphur contains 6.02×10²³ atoms.
1 mole of sulphur = 32 g
Thus,
32 g of sulphur contains 6.02×10²³ atoms.
Therefore, 5.59 g of sulphur will contain = (5.59 × 6.02×10²³) / 32 = 1.05×10²³ atoms.
From the calculations made above, 5.59 g of sulphur contains 1.05×10²³ atoms.
Finally, we shall determine the mass of silver that contains 1.05×10²³ atoms.
This is illustrated below:
1 mole of silver = 6.02×10²³ atoms.
1 mole of silver = 108 g
108 g of silver contains 6.02×10²³ atoms.
Therefore, Xg of silver will contain 1.05×10²³ atoms i.e
Xg of silver = (108 × 1.05×10²³)/6.02×10²³
Xg of silver = 18.84 g
Thus, 18.84 g of silver contains the same number of atoms (i.e 1.05×10²³ atoms) as 5.59 g of sulfur
Answer:
ΔG < 0
Explanation:
The condition for spontaneity of a chemical reaction is that ∆G<0. Hence for any biochemical reaction to proceed as written, ∆G must have a negative value.
If ∆G >0, the reaction is not spontaneous and will not proceed as written. ∆G=0 means that the reaction has attained equilibrium.
Putting them in that oder can be absolutely wrong becaus they are not in the same group of the periodic table
Answer:
17.136 g H2
Explanation:
First we need to convert moles of Zinc to moles of Hydrogen in order to find out how many moles of hydrogen are produced.
When we look at our balanced equation, we can see that for every mole of Zn reacting, there is 1 mol of H2 produced. (imagine a 1 in front of the elements that have no numbers in front of them)
8.5 mol Zn * 
= 8.5 mol H2
Now we will convert from moles of Hydrogen to grams
The atomic mass of H2 is 2(1.008) g/1 mol... so we will use this to convert to the number of grams of Hydrogen produced..
8.5 mol H2 * 
= 17.136 g H2
