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IRINA_888 [86]
3 years ago
7

Which of these objects could be falling with constant acceleration?

Physics
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer:

1 and 2

Explanation:

If an object has constant acceleration, it's displacement at time t is:

Δx = v₀ t + ½ at²

For object 1:

0.44 = (0) (0.3) + ½ a (0.3)²

a = 9.78

3.14 = (0) (0.8) + ½ a (0.8)²

a = 9.81

So object 1's acceleration is approximately constant.

For object 2:

0.06 = (0) (0.3) + ½ a (0.3)²

a = 1.33

3.09 = (0) (2.1) + ½ a (2.1)²

a = 1.40

So object 2's acceleration is approximately constant.

For object 3:

0.44 = (0) (0.3) + ½ a (0.3)²

a = 9.78

3.09 = (0) (2.1) + ½ a (2.1)²

a = 1.40

So object 3's acceleration is not constant.

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masha68 [24]

To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

T = 2\pi \sqrt{\frac{l}{g}}

Where

l = Length

g = Gravity

Re-arrange to find L,

L = g (\frac{T}{2\pi})^2

Our values are given as

g = 9.81m/s

T = 10.1s

Replacing,

L = g (\frac{T}{2\pi})^2

L = (9.81) (\frac{10.1}{2\pi})^2

L = 25.348m

Therefore the height would be 25.348m

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3 years ago
You ride your bike for a distance of 30 km. You travel at a speed of 0.75 km/ minute. How many minutes does this take?
dolphi86 [110]
(30 km)/(0.75 km/min) = 40 min
4 0
3 years ago
Read 2 more answers
A single mass (m1 = 3.5 kg) hangs from a spring in a motionless elevator. The spring constant is k = 278 N/m. 1)What is the dist
artcher [175]
<h2>Answer:</h2>

0.126m

<h2>Explanation:</h2>

According to Hooke's law, the force (F) acting on a spring to cause an extension or compression (e) is given by;

F = k x e            -------------------(i)

Where;

k = the spring's constant.

From the question, the force acting on the spring is the weight(W) of the mass. i.e

F = W               -----------------------(ii)

<em>But;</em>

W = m x g;

where;

m = mass of the object

g = acceleration due to gravity [usually taken as 10m/s²]

<em>From equation (ii), it implies that;</em>

F = W = m x g

<em>Now substitute F = m x g into equation(i) as follows;</em>

F = k x e

m x g = k x e      ------------------(iii)

<em>From the question;</em>

m = m1 = 3.5kg

k = 278N/m

<em>Substitute these values into equation (iii) as follows;</em>

3.5 x 10 = 278 x e

35 = 278e

<em>Now solve for e;</em>

e = 35/278

e = 0.126m

Therefore, the distance the spring is stretched from its unstretched length (which is the same as the extension of the spring) is 0.126m

3 0
3 years ago
Describe a ball's motion as it rolls up a slanted
emmasim [6.3K]

The ball will decelerate as it moves upwards.

The magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

The given parameters;

  • initial velocity of the ball, u = 1.25 m/s
  • time of motion of the ball, t = 4.22 s

As the ball rolls up the inclined plane, the velocity decreases and eventually becomes zero when the ball reaches the highest point of the plane.

Thus, the ball decelerate as it moves upwards.

The acceleration of the ball is calculate as;

a = \frac{v_f -v_0}{t} \\\\

<em>at the highest point on the incline plane, the final velocity </em>v_f<em> is zero</em>

a = \frac{0-1.25}{4.22} \\\\a = -0.3 \ m/s^2

Thus, the magnitude of the ball's acceleration is 0.3 m/s² and it directed backwards.

Learn more here:brainly.com/question/23860763

4 0
3 years ago
• ¿Qué rapidez tendrá un sonido de 150 Hz con una longitud de onda de 2 metros?
kobusy [5.1K]

Answer:

Speed = 300 m/s

Explanation:

Given the following data;

Frequency = 150 Hz

Wavelength = 2 meters

To find the speed of the wave;

Mathematically, the speed of a wave is given by the formula:

Speed = wavelength * frequency

Substituting into the formula, we have;

Speed = 2 * 150

Speed = 300 m/s

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