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3 years ago

Which of these objects could be falling with constant acceleration?

Physics

1 answer:

LuckyWell [14K]3 years ago

5 0

Answer:

1 and 2

Explanation:

If an object has constant acceleration, it's displacement at time t is:

Δx = v₀ t + ½ at²

For object 1:

0.44 = (0) (0.3) + ½ a (0.3)²

a = 9.78

3.14 = (0) (0.8) + ½ a (0.8)²

a = 9.81

So object 1's acceleration is approximately constant.

For object 2:

0.06 = (0) (0.3) + ½ a (0.3)²

a = 1.33

3.09 = (0) (2.1) + ½ a (2.1)²

a = 1.40

So object 2's acceleration is approximately constant.

For object 3:

0.44 = (0) (0.3) + ½ a (0.3)²

a = 9.78

3.09 = (0) (2.1) + ½ a (2.1)²

a = 1.40

So object 3's acceleration is not constant.

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6. A 4 kg object hangs below a 6 kg object by a string of negligible mass. If the 6 kg object is pulled upward by a force of 440

MrRissso [65]

Answer:

T =176 N

Explanation:

from diagram

F -(m_1+m_2_g) = (m_1+m_2_g)a

440 - (6+4)g = (6+4)a

a =\frac{440-10*9.8}{10}

a =34.2 m/s^2

frrom free body diagram of mass m2 = 4kg

T -m_2g =m_2a

T = m_2(g +a)

T = 4(9.81+34.2)

T =176 N

7 0

3 years ago

A camera, a drill, and a hand-squeeze flashlight use either a generator or a motor as a component. Identify which component each

muminat

A camera is a motor.

A drill is a motor.

A hand-squeeze flashlight is a generator.

Hope this helped :)

4 0

3 years ago

Read 2 more answers

When the mass of an object decreases, the force of gravity

Viktor [21]

Hello There!

From what i know, gravitational force increases if the mass is increased.
If the mass is being decreased, then i assume it will be B. Decreases.

Hope This Helps You!
Good Luck :)

- Hannah ❤

8 0

3 years ago

Find an expression for the electric field E⃗ at the center of the semicircle. Hint: A small piece of arc length Δs spans a small

Hatshy [7]

Answer:

Electric Field a the centre $E=\dfrac{Q}{2\pi^2\epsilon_0 R^2}(-\vec j)$

Explanation:

<u>Given:</u>

Total charge on the semicircle =Q

Radius of the semicircle=R

Let consider a elemental charge on the semicircle at an angle $\theta\\$ with the horizontal. Since the The charge distribution is symmetrical about y axis so the there will symmetrical charge on other side. The horizontal component will cancel out each other and vertical component will get added so let dE be the electric Field due to elemental charge

Let $\lambda$ be the charge per unit length such that $\lambda=\dfrac{Q}{\pi R}$

$k=\dfrac{1}{4\pi \epsilon_0}$

Total Electric Field at the centre

$=2dE\sin\theta\\=2\dfrac{k\lambda }{R}\int \sin \theta d\theta\\$

integrating 0 to $\dfrac{\pi}{2}$

$E=\dfrac{2k\lambda}{R}(-\vec j)$

$E=\dfrac{Q}{2\pi^2\epsilon_0 R^2}(-\vec j)$

So the Electric field at the centre is calculated.

7 0

3 years ago

A cannonball is shot out of a long cannon and then a short cannon with the same amount of force. The short cannon cannonball has

Dvinal [7]

Answer:

The correct answer is less momentum.

Explanation:

The momentum of an object is directly linked to the force exerted on that object. In a longer barrel, the shot cannonball will have a greater impulse changing to occur a larger momentum and therefore a higher speed will be applied to the bullet, contrary to what would happen in a shorter barrel.

8 0

3 years ago