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IRINA_888 [86]
3 years ago
7

Which of these objects could be falling with constant acceleration?

Physics
1 answer:
LuckyWell [14K]3 years ago
5 0

Answer:

1 and 2

Explanation:

If an object has constant acceleration, it's displacement at time t is:

Δx = v₀ t + ½ at²

For object 1:

0.44 = (0) (0.3) + ½ a (0.3)²

a = 9.78

3.14 = (0) (0.8) + ½ a (0.8)²

a = 9.81

So object 1's acceleration is approximately constant.

For object 2:

0.06 = (0) (0.3) + ½ a (0.3)²

a = 1.33

3.09 = (0) (2.1) + ½ a (2.1)²

a = 1.40

So object 2's acceleration is approximately constant.

For object 3:

0.44 = (0) (0.3) + ½ a (0.3)²

a = 9.78

3.09 = (0) (2.1) + ½ a (2.1)²

a = 1.40

So object 3's acceleration is not constant.

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A fixed mass of an ideal gas has a volume of 800 cm3 under certain conditions. The pressure (in kPa) and temperature (in K) are
Mashutka [201]

Answer:

800cm3

Explanation:

This is a general gas law question

Which has the relationship P1V1/T1 = P2V2/T2

P1= P1 in kPa

T1 = T1 in K

V1= 800cm3

V2=?

P2= 2* P1

T2= 2*T1

The volume of gas after the changes (V2), making it as the subject of formula

V2= P1*V1*T2/P2*T1

V2 = P1 *800* 2T1 / 2P1 * T1 ; dividing accordingly, we have

V2 = 800cm3

3 0
4 years ago
A 3.0 kg cart moving due east at 4.0 m/s collides with a 6.0 kg cart moving due west. the carts stick together and come to rest
denpristay [2]
The problem about describes a perfectly inelastic collision. We are tasked to find the initial velocity of an object having a mass of 6 kg moving due west. It is given in the problem that after collision the cart sticks together and it stops. Thus, the final mass is the sum of the two cart and the final velocity is zero. For a perfectly inelastic collision,

m1v1-m2v2=vf(m1+m2)
By Substitution,

3(4)-6(v2)=0
6v2=12
v2=2

Therefor, the initial velocity if a 6 kg cart is 2 m/s
3 0
4 years ago
Ethan, whose mass is 67 kg , stands at one end of a very long, stationary wheeled cart that has a mass of 500 kg . He then start
Anvisha [2.4K]

Answer:

v = -0.938 m/s ( the negative sign indicating the direction of the cart is opposite the motion of Ethan)

Explanation:

mass of Ethan (Me) = 67 kg

mass of cart (Mc) = 500 kg

Ethan's top speed (Ts) = 8 m/s

let the velocity of the cart be v

relative to the earth, Ethan will be moving forward while the cart will be moving backward, therefore

Ethan,s velocity relative to the earth = 8 -v,

apply the conservation of momentum equation

MeUe + McUc = MeVe + McVc

where Ue and Uc are the initial velocities of Ethan and the cart and are all zero, the left side of the equation is equal to zero

0 = MeVe + McVc

0 = (67 x (8-v)) + (500 x v)

0 = 536v - 67v + 500v

0 = 469 + 500v

v = -469/500

v = -0.938 m/s ( the negative sign indicating the direction of the cart is opposite the motion of Ethan)

4 0
4 years ago
Where does the energy that heats the Moon's rocks come from? How does it get there?
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Some of it may be from tidal heating, but the majority of it is probably from the decay of radioactive material. Its unlikely that there is any heat left over from when the Moon formed, when it was molten.
3 0
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Momentum is mass times distancevelocityaccelerationtime
8_murik_8 [283]
To calculate momentum, one would multiply an object's mass to the velocity of that particular object.

P = m • v
P = momentum
m = mass
v = velocity.
3 0
3 years ago
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