Question

Which volume of 0.600 M H2SO4(aq) exactly neutralizes 100. milliliters of 0.300 M Ba(OH)2(aq)?

Answer 1

Answer: 50 ml of 0.600 M of sulfuric acid will exactly neutralize the 100 ml of 0.300 M of barium hydroxide solution.

Explanation:

$H_2SO_4+Ba(OH)_2\rightarrow BaSO_4+2H_2O$

According to reaction 1 mole sulfuric acid neutralizes 1 mole oh barium hydroxide.

$M_1=0.600 M,H_2SO_4$

$V_1=?$

$M_2=0.300 M,Ba(OH)_2$

$V_2=100 ml$

$M_1V_1=M_2V_2$

$V_1=\frac{M_2\times V_2}{M_1}=50 ml$

50 ml of 0.600 M of sulfuric acid will exactly neutralize the 100 ml of 0.300 M of barium hydroxide solution.

Answer 2

50.0 ml
this because i got it from castle learning lol
-9th grader