First, it makes your skin feel cooler<span> when it's wet. And when it </span>evaporates<span> it removes some heat. But sweat will only </span>evaporate<span> in an environment where there isn't much</span>water<span> in the air. In a place with high humidity, there're already lots of </span>water<span> molecules in the air. </span>
Answer:
Explanation:
A Spring stretches / compresses when force is applied on them and they are governed by the Hookes Law which states that the force required to stretch or compress a spring is directly proportional to the distance it is stretched.

F is the force applied and x is the elongation of the spring
k is the spring constant.
negative sign indicates the change in direction from equilibrium position.
In the given question, we dont have force but we know that the pan is hanging. We also know from the Newton's second law of motion that

Inserting this into Hooke's Law

computing it for x,

This is the model which will tell the length of the spring against change in the mass located in the pan.
The resonant frequency of a circuit is the frequency
at which the equivalent impedance of a circuit is purely real (the imaginary part is null).
Mathematically this frequency is described as

Where
L = Inductance
C = Capacitance
Our values are given as


Replacing we have,



From this relationship we can also appreciate that the resonance frequency infers the maximum related transfer in the system and that therefore given an input a maximum output is obtained.
For this particular case, the smaller the capacitance and inductance values, the higher the frequency obtained is likely to be.
Answer: because they have equal numbers of protons
Explanation: Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom gains or loses one or more electrons, it becomes an ion
Explanation:
<em>Light</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>form</em><em> </em><em>of</em><em> </em><em>energy</em><em> </em><em>that</em><em> </em><em>travels</em><em> </em><em>as</em><em> </em><em>waves</em><em>.</em>