<h2>Answer: about the same size of the gap
</h2>
Diffraction happens when a wave (mechanical or electromagnetic wave, in fact, any wave) meets an obstacle or a slit .When this occurs, the wave bends around the corners of the obstacle or passes through the opening of the slit that acts as an obstacle, forming multiple patterns with the shape of the aperture of the slit.
Note that the principal condition for the occurrence of this phenomena is that <u>the obstacle must be comparable in size (similar size) to the size of the wavelength.
</u>
<u></u>
In other words, <u>when the gap (or slit) size is larger than the wavelength</u>, the wave passes through the gap and does not spread out much on the other side, but when the gap size is equal to the wavelength, maximum diffraction occurs and the waves spread out greatly.
Therefore:
<h2>
Waves diffract the most when their wavelength is <u>about the same size of the gap</u>
</h2>
Answer:
B
Explanation:
the Halogen families have 7 valence electrons
25 m/s² is the object's acceleration
m1a1=m2a2
m1=5kg
m2=3 kg
a1= 15 m/s²
a2=?
m1a1=m2a2
a2=m1a1/m2
a2=5×15÷3
a2= 25 m/s²
Acceleration is a vector variable that describes the rate at which an object changes its velocity.
An object is said to be accelerating if its velocity is changing. Occasionally, a moving object can change its velocity by the same amount each second. a moving object whose speed fluctuates by 10 m/s every second. This is referred to as a constant acceleration since the velocity is changing by a fixed amount each second.
The difference between an object with a constant acceleration and one with a constant velocity must be understood. Do not be fooled! If an object's velocity changes, whether it does so by a constant amount or a variable amount, then it is accelerating. Furthermore, something that is travelling at a steady speed is not accelerating.
To know more about acceleration visit : brainly.com/question/3046924
#SPJ9
Answer:
2.11 seconds
Explanation:
We use the kinematic equation for the velocity in a constantly accelerated motion under the acceleration of gravity (g):

Answer:
the answer to this question is 288