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horrorfan [7]
3 years ago
14

A confused student was doing an isomer problem and listed the following six names as different structural isomers of C7H16. a. 1

-sec-butylpropane b. 4-methylhexane c. 2-ethylpentane d. 1-ethyl-1-methylbutane e. 3-methylhexane f. 4-ethylpentane How many different structural isomers are actually present in these six names?

Chemistry
2 answers:
avanturin [10]3 years ago
7 0

Answer:

One different structural formula is actually correct/present in the six names

Explanation:

Structural isomers are compounds with the same molecular formula but different structural formulas. The major problem this student had was with the naming of the isomers. For example

4-methylhexane is wrong because the methyl supposedly on the 4th carbon is too close to the end of the carbon chain and should have been counted in the reversed direction as 3-methylhexane.

2-ethylpentane is also wrong because ethyl cannot be found on the second carbon as a branch, hence, the branch will be the last carbon attached to the supposed second carbon (which is actually the third carbon), making the supposed ethyl part of the longest continuous carbon chain. The actual name ought to be 3-methylhexane.

1-ethyl-1-methylbutane is also wrong because the first/last carbon of the carbon chain does not take a branch as it forms part of the longest continuous carbon chain. Hence, the right name here is 3-methylhexane

4-ethylpentane is wrong. Again, the ethyl group is supposedly on the fourth carbon which is too close to the end of the carbon chain and hence should have been counted in the reverse direction. The correct name is 3-methylhexane.

The only correct structural isomer the student presented is 3-methylhexane (e).

klasskru [66]3 years ago
4 0

In case of heptane (C7H16) the following structural isomers are possible

shown in figure

a. 1-sec-butylpropane : this is actually 3-methyl hexane

b. 4-methylhexane : this is actually 3-methylhexane

c. 2-ethylpentane : this is actually 3-methyl hexane

d. 1-ethyl-1-methylbutane: 3-methylhexane

e. 3-methylhexane: correct IUPAC

f. 4-ethylpentane: This is actually 3-methylhexane

Hence all represent single isomer

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kakasveta [241]

Answer:

0.292 g/mL.

Explanation:

From the question given above, the following data were obtained:

Mass of object = 28.1 g

Volume of object = 96.2 mL

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Density of an object is simply defined as the mass of the object per unit volume of the object. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the object as follow:

Mass of object = 28.1 g

Volume of object = 96.2 mL

Density of object =..?

Density = mass / volume

Density = 28.1 / 96.2

Density of object = 0.292 g/mL

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3 0
3 years ago
In this experiment we will be using a 0.05 M solution of HCl to determine the concentration of hydroxide (OH-) in a saturated so
gulaghasi [49]

<u>Answer:</u> The moles of hydroxide ions present in the sample is 0.0008 moles

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=0.05M\\V_1=16mL\\n_2=2\\M_2=?M\\V_2=36.0mL

Putting values in above equation, we get:

1\times 0.05\times 16=2\times M_2\times 36\\\\M_2=\frac{1\times 0.05\times 16}{2\times 36}=0.011M

To calculate the moles of hydroxide ions, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

Molarity of solution = 0.011 M

Volume of solution = 36.0 mL

Putting values in above equation, we get:

0.011=\frac{\text{Moles of }Ca(OH)_2\times 1000}{36}\\\\\text{Moles of }Ca(OH)_2=\frac{0.011\times 36}{1000}=0.0004mol

1 mole of calcium hydroxide produces 1 mole of calcium ions and 2 moles of hydroxide ions.

Moles of hydroxide ions = (0.0004 × 2) = 0.0008 moles

Hence, the moles of hydroxide ions present in the sample is 0.0008 moles

8 0
3 years ago
Without doing any calculations, match the following thermodynamic properties with their appropriate numerical sign for the follo
siniylev [52]

Answer:

∆H > 0

∆Srxn <0

∆G >0

∆Suniverse <0

Explanation:

We are informed that the reaction is endothermic. An endothermic reaction is one in which energy is absorbed hence ∆H is positive at all temperatures.

Similarly, absorption of energy leads to a decrease in entropy of the reaction system. Hence the change in entropy of the reaction ∆Sreaction is negative at all temperatures.

The change in free energy for the reaction is positive at all temperatures since ∆S reaction is negative then from ∆G= ∆H - T∆S, we see that given the positive value of ∆H, ∆G must always return a positive value at all temperatures.

Since entropy of the surrounding= - ∆H/T, given that ∆H is positive, ∆S surrounding will be negative at all temperatures. This is so because an endothermic reaction causes the surrounding to cool down.

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3 years ago
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Answer:

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tino4ka555 [31]

Answer:

\%\ Composition\ of\ phosphorus=20.00\ \%

Explanation:

The molecular formula of the monohydrate formed = MgNH_4PO_4.H_2O

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\%\ Composition\ of\ phosphorus =\frac{Mass_{phosphorus}}{Total\ mass}\times 100

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\%\ Composition\ of\ phosphorus=20.00\ \%

4 0
3 years ago
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