c. Some health risks are increased by heredity, which manifest under certain environmental conditions.
<h3>The chance of contracting some diseases can arise in particular circumstances.</h3>
The occurrence of certain diseases is influenced by certain environmental factors. Air pollution from a polluted environment increases the chance of allergic people or those with overactive immune systems acquiring respiratory conditions like asthma. A similar genetic flaw in melanin formation increases the risk of skin cancer in people who are exposed to UV rays. As a result, certain circumstances promote the development of disease.
Communities can lessen exposure to diseases and chemicals that have damaging effects on the body by focusing on environmental health. Environmental health treatments can improve everyone's quality of life, but they may be especially noticeable for people with pre-existing health conditions.
Learn more about environmental health here:
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Answer:
No, CCl₄ is 4 covalent C-Cl single bonds with a Tetrahedral geometry.
Explanation:l
For resonance structures to exist the molecule must have alternating single-double bonds. H₂C = CH - CH₃ <=> H₃C - CH = CH₂ resents a simple compound with a resonance structure system. This means that the π-bond electrons are distributed across all carbons in the molecular backbone. I would recommend internet searching for Danial Weeks 'Pushing Electrons' for a comprehensive review of molecular resonance structures. It is a brief, but easy to follow treatment of simple to complex structures containing resonance systems.
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m/1,609.344=mi (meters divided by 1,609.344 equals miles)
Answer:
The compound is N2O4
Explanation:
We have certain important pieces of information about the compound;
1) it is an oxide (a binary compound of nitrogen and oxygen)
2) there are no N-N bonds present
3) there are no O-O bonds present
Since it contains only nitrogen and oxygen then nitrogen accounts for 25.9% of the molecule by mass then oxygen should account for (100-25.9) = 74.1% oxygen
Relative atomic mass of oxygen = 16
Relative atomic mass of nitrogen = 14
We now deduce the empirical formula
Nitrogen. Oxygen
25.9/14. 74.1/16
1.85/1.85. 4.6/1.85 (divide through by the lowest ratio)
1 2
Empirical formula is NO2
To find the molecular formula
(NO2)n = 108
(14+2(16))n= 108
46n=108
n= 108/46
n= 2
Therefore molecular formula= N2O4