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enot [183]
3 years ago
15

Which of the following is NOT true of fusion?

Physics
2 answers:
DaniilM [7]3 years ago
7 0

Hey there!

The correct choice is C. Used in nuclear power plants

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

Gekata [30.6K]3 years ago
6 0
C., used in power plants I think. 
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If the load on Pulley E is 20N, how much effort is needed to life it?
Mariana [72]
It would need to be over 20 because if the load of the Pulley E is 20 and the effort is 20, then they will be equal and the Pulley would not move, so your answer is at least 20
7 0
3 years ago
A student lefts a bouncy ball to 1.2m, then releases the ball. The ball bounces back up to 0.86m. Construct an explanation as to
Airida [17]

Answer:

the decrease in energy is due to a transformational in internal energy of the body in the rebound.

Explanation:

For this exercise we can calculate the initial and final mechanical energy

        Em₀ = U = m g y₁

        Em_{f} = U = m g y₂

we look for the variation of the energy

       ΔEm = Em_{f} - Em₀

       ΔEm = m g (y_{f} -y₀)

       ΔEm = m g (0.86 -1.2)

       ΔEm = -3.332 m

We can see that there is a decrease in mechanical energy, this is transformed into internal energy of the ball during the impact with the ground, this energy can be formed by several factors such as a part of the friction with the surface, an increase in body temperature or a deformation of the body; there may be a contribution from several of these factors.

In conclusion the decrease in energy is due to a transformational in internal energy of the body in the rebound.

7 0
3 years ago
Read 2 more answers
The acceleration of a particle is defined by the relation a 5 28 m/s2. Knowing that x 5 20 m when t 5 4 s and that x 5 4 m when
mamaluj [8]

Explanation:

It is given that,

The acceleration of a particle, a=-8\ m/s^2 (negative as the particle is decelerating)

Initial distance, x₁ = 20 m

Initial time, t₁ = 4 s

New distance x₂ = 4 m

Velocity, v = 10 m/s

(A) Calculating initial distance using second equation of motion as :

x_1=ut_1+\dfrac{1}{2}at^2

20=4u+\dfrac{1}{2}(-8)\times 4^2

u = 21 m/s

When velocity of the particle is zero, time taken is t (say). Using first equation of motion as :

v=u+at

0=21+(-8)t

t = 2.62 seconds

So, the velocity of the particle is zero at t = 2.62 seconds.

(B) Velocity at t = 11 s

v=21+(-8)\times 11

v = 13 m/s

Total distance covered at t = 11 s. The overall path travelled by the particle during its entire journey is called total distance covered.

d=ut+\dfrac{1}{2}at^2+|ut+\dfrac{1}{2}at^2|

d=21\times 2.62+\dfrac{1}{2}\times (-8)(2.62)^2+|21\times 8.38+\dfrac{1}{2}\times (-8)(8.38)^2|

d = 132.48 m

So, the distance travelled by the particle at t = 11 seconds is 132.48 meters.    

5 0
2 years ago
A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car
Novay_Z [31]

Answer:

4.5 *10^{3}\ kgm/s^{2}

Explanation:

Given:

Mass= 1.00 * 10^{3} \ kilograms,\\Acceleration =4.5\  meters/second^{2}

As we know that

Force=Mass * Acceleration

Putting the value of mass and Acceleration  we get ,

Force\  = \ 1.00 * 10^{3} * 4.5\ m/s^{2}

Force\  =4.5 * \ 10^{3} \  kgm/s^{2}

Therefore Net force is :4.5 *10^{3}\ kgm/s^{2}

0 0
2 years ago
A spring with a spring constant of 50 N/m is stretched by an extension of 2 cm. Calculate the energy in its elastic energy poten
MAVERICK [17]

Answer:

0.01 J

Explanation:

E = ½ kx²

E = ½ (50 N/m) (0.02 m)²

E = 0.01 J

6 0
3 years ago
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