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enot [183]
3 years ago
15

Which of the following is NOT true of fusion?

Physics
2 answers:
DaniilM [7]3 years ago
7 0

Hey there!

The correct choice is C. Used in nuclear power plants

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

Gekata [30.6K]3 years ago
6 0
C., used in power plants I think. 
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A car (mass 1200 kg, speed 100 km/h) and a truck (mass 2800 kg, speed 50 km/h) are moving in the same direction along a highway.
Sloan [31]

Answer:

Speed of the wreck after the collision is 65 km/h

Explanation:

When a car hits truck and sticks together, the  collision would be totally inelastic.  Since the both the vehicles  locked  together, they have the same final velocity.

Mass of car  m_{1}=1200 kg

Mass of truck m_{2}=2800 kg

Initial speed of the car u_{1}=100 km /h

Initial speed  of the truck u_{2}=50 km /h

The final velocity of the wreck will be

m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}

since final speed are same, v_{1}=v_{2}=v

m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v

1200\times 100 +2800 \times 50 =(1200+2800)v\\v=\frac{260000}{4000} \\v=65 km/h

5 0
3 years ago
1.a bag is dropped from a hovering helicopter. the bag has fallen for 2 s. what is the ball's velocity at the instant its hittin
omeli [17]

1. The bag's velocity immediately before hitting the ground.

Recall this kinematics equation:

Vf = Vi + aΔt

Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and Δt is the time elapsed.

Given values:

Vi = 0m/s (you assume this because the bag is dropped, so it falls starting from rest)

a is 9.81m/s² (this is the near-constant acceleration of objects near the surface of the earth)

Δt = 2s

Plug in the values and solve for Vf:

Vf = 0 + 9.81×2

Vf = 19.62m/s

2. The height of the helicopter.

Recall this other kinematics equation:

d = ViΔt + 0.5aΔt²

d is the distance traveled by the object, Vi is the initial velocity, a is the acceleration, and Δt is the time elapsed.

Given values:

Vi = 0m/s (bag is dropped starting from rest)

a = 9.81m/s² (acceleration due to gravity of the earth)

Δt = 2s

Plug in the values and solve for d:

d = 0×2 + 0.5×9.81×2²

d = 19.62m

3. Time of the bag's fall and its velocity immediately before hitting the ground... if it started falling at 2m/s

Reuse the equation from question 2:

d = ViΔt + 0.5aΔt²

Given values:

d = 19.6m (height of the helicopter obtained from question 2)

Vi = 2m/s

a = 9.81m/s² (acceleration due to earth's gravity)

Plug in the values and solve for Δt:

19.6 = 2Δt + 0.5×9.81Δt²

4.91Δt² + 2Δt - 19.6 = 0

Use the quadratic formula to get values of Δt (a quick Google search will give you the formula and how to use it to solve for unknown values):

Δt = 1.8s, Δt = −2.2s

The formula gives us 2 possible answers for Δt but within the situation of our problem, only the positive value makes sense. Reject the negative value.

Δt = 1.8s

Now we can use this new value of Δt to get the velocity before hitting the ground:

Vf = Vi + aΔt

Given values:

Vi = 2m/s

a = 9.81m/s²

Δt = 1.8s (result from previous question)

Plug in the values and solve for Vf:

Vf = 2 + 9.81×1.8

Vf = 19.66m/s

4 0
3 years ago
After an initial test run John determines that his cooling system generates 45 W of heat loss. Calculate the amount of heat loss
anyanavicka [17]

Given:

heat generated by John's cooling system,  H = \rho A v^{3}  = 45 W    (1)

If ρ, A, and v corresponds to John's cooling system then let \rho_{1}, A_{1}, v_{1} be the variables for Mike's system then:

\rho  = 9.5\rho_{1}

\rho_{1}  = \frac{\rho}{9.5}

v_{1} =3.5 v

Formula use:

Heat generated, H = \rho A v^{3}

where,

\rho = density

A = area

v = velocity

Solution:

for Mike's cooling system:

H_{2} = v_{1}^{3}{1}A_{1}\rho_{1}

⇒ H_{2} = (3.5v)^{3} × A × \frac{\rho}{9.5}

H_{2} = 4.513v^{3} A  \rho

Using eqn (1) in the above eqn, we get:

H_{2} = 4.513 × 45 = 203.09 W

5 0
3 years ago
a kid is flying a kite 58 meters above the level ground. a small lead sphere is dropped from the kite. calculate the amount of t
Fynjy0 [20]

This is the formula you need to memorize:  

D = 1/2 · a · T²

Distance = (1/2) · (acceleration) · (Time²)

This formula tells the distance an object falls in any amount of time.

This question tells you the distance (58m), and you know the acceleration (gravity, 9.8 m/s²), so you can use this formula to find the time.

Distance = (1/2) · (acceleration) · (Time²)

58m  =  (1/2) · (9.8 m/s²) · (Time²)

Divide each side by (4.9 m/s²) :  Time²  =  (58/4.9) seconds²

Take the square root of each side:  <em>Time = 3.44 seconds  </em>

6 0
3 years ago
Function of bones in the body?
Alex17521 [72]

Any of the pieces of hard whitish tissue making up the skeleton in humans and other vertebrates.

The calcified material of which bones consist

8 0
3 years ago
Read 2 more answers
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