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3 years ago

15

Which of the following is NOT true of fusion?

2 answers:

DaniilM [7]3 years ago

7 0

Hey there!

The correct choice is C. Used in nuclear power plants

Hope this helps you!

God bless ❤️

xXxGolferGirlxXx

Gekata [30.6K]3 years ago

6 0

C., used in power plants I think.

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A car (mass 1200 kg, speed 100 km/h) and a truck (mass 2800 kg, speed 50 km/h) are moving in the same direction along a highway.

Sloan [31]

Answer:

Speed of the wreck after the collision is 65 km/h

Explanation:

When a car hits truck and sticks together, the collision would be totally inelastic. Since the both the vehicles locked together, they have the same final velocity.

Mass of car $m_{1}=1200 kg$

Mass of truck $m_{2}=2800 kg$

Initial speed of the car $u_{1}=100 km /h$

Initial speed of the truck $u_{2}=50 km /h$

The final velocity of the wreck will be

$m_{1}u_{1}+m_{2}u_{2}=m_{1}v_{1}+m_{2}v_{2}$

since final speed are same, $v_{1}=v_{2}=v$

$m_{1}u_{1}+m_{2}u_{2}=(m_{1}+m_{2})v$

$1200\times 100 +2800 \times 50 =(1200+2800)v\\v=\frac{260000}{4000} \\v=65 km/h$

5 0

3 years ago

1.a bag is dropped from a hovering helicopter. the bag has fallen for 2 s. what is the ball's velocity at the instant its hittin

omeli [17]

1. The bag's velocity immediately before hitting the ground.

Recall this kinematics equation:

Vf = Vi + aΔt

Vf is the final velocity, Vi is the initial velocity, a is the acceleration, and Δt is the time elapsed.

Given values:

Vi = 0m/s (you assume this because the bag is dropped, so it falls starting from rest)

a is 9.81m/s² (this is the near-constant acceleration of objects near the surface of the earth)

Δt = 2s

Plug in the values and solve for Vf:

Vf = 0 + 9.81×2

Vf = 19.62m/s

2. The height of the helicopter.

Recall this other kinematics equation:

d = ViΔt + 0.5aΔt²

d is the distance traveled by the object, Vi is the initial velocity, a is the acceleration, and Δt is the time elapsed.

Given values:

Vi = 0m/s (bag is dropped starting from rest)

a = 9.81m/s² (acceleration due to gravity of the earth)

Δt = 2s

Plug in the values and solve for d:

d = 0×2 + 0.5×9.81×2²

d = 19.62m

3. Time of the bag's fall and its velocity immediately before hitting the ground... if it started falling at 2m/s

Reuse the equation from question 2:

d = ViΔt + 0.5aΔt²

Given values:

d = 19.6m (height of the helicopter obtained from question 2)

Vi = 2m/s

a = 9.81m/s² (acceleration due to earth's gravity)

Plug in the values and solve for Δt:

19.6 = 2Δt + 0.5×9.81Δt²

4.91Δt² + 2Δt - 19.6 = 0

Use the quadratic formula to get values of Δt (a quick Google search will give you the formula and how to use it to solve for unknown values):

Δt = 1.8s, Δt = −2.2s

The formula gives us 2 possible answers for Δt but within the situation of our problem, only the positive value makes sense. Reject the negative value.

Δt = 1.8s

Now we can use this new value of Δt to get the velocity before hitting the ground:

Vf = Vi + aΔt

Given values:

Vi = 2m/s

a = 9.81m/s²

Δt = 1.8s (result from previous question)

Plug in the values and solve for Vf:

Vf = 2 + 9.81×1.8

Vf = 19.66m/s

4 0

3 years ago

After an initial test run John determines that his cooling system generates 45 W of heat loss. Calculate the amount of heat loss

anyanavicka [17]

Given:

heat generated by John's cooling system, $H = \rho A v^{3}$ = 45 W (1)

If ρ, A, and v corresponds to John's cooling system then let $\rho_{1}, A_{1}, v_{1}$ be the variables for Mike's system then:

$\rho = 9.5\rho_{1}$

$\rho_{1} = \frac{\rho}{9.5}$

$v_{1} =3.5 v$

Formula use:

Heat generated, $H = \rho A v^{3}$

where,

$\rho$ = density

A = area

v = velocity

Solution:

for Mike's cooling system:

$H_{2}$ = $v_{1}^{3}{1}A_{1}\rho_{1}$

⇒ $H_{2}$ = $(3.5v)^{3}$ × A × $\frac{\rho}{9.5}$

$H_{2}$ = 4.513 $v^{3}$ A $\rho$

Using eqn (1) in the above eqn, we get:

$H_{2}$ = 4.513 × 45 = 203.09 W

5 0

3 years ago

a kid is flying a kite 58 meters above the level ground. a small lead sphere is dropped from the kite. calculate the amount of t

Fynjy0 [20]

This is the formula you need to memorize:

D = 1/2 · a · T²

Distance = (1/2) · (acceleration) · (Time²)

This formula tells the distance an object falls in any amount of time.

This question tells you the distance (58m), and you know the acceleration (gravity, 9.8 m/s²), so you can use this formula to find the time.

Distance = (1/2) · (acceleration) · (Time²)

58m = (1/2) · (9.8 m/s²) · (Time²)

Divide each side by (4.9 m/s²) : Time² = (58/4.9) seconds²

Take the square root of each side: <em>Time = 3.44 seconds </em>

6 0

3 years ago

Function of bones in the body?

Alex17521 [72]

Any of the pieces of hard whitish tissue making up the skeleton in humans and other vertebrates.

The calcified material of which bones consist

8 0

3 years ago

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