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Dima020 [189]
3 years ago
15

Is it possible for an object's weight to change while its mass remains constant

Physics
1 answer:
guajiro [1.7K]3 years ago
8 0
Yes. Take it off of the Earth's surface, farther away from the center of the Earth.

If you REALLY want its weight to change, take it into orbit, or to the Moon, or to Jupiter.
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When did Pangaea begin to break apart?
harkovskaia [24]

Answer:

Hey!

Well according to scientific data and analysis, it started to break up about 175 - 200 million years ago!!

Explanation:

HOPE THIS HELPS!!

4 0
4 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
4 years ago
A rectangular box has side 10cm x 5cm x 2cm. If it lies on a horizontal surface and has weight 1.00N, calculate the maximum and
Vladimir [108]

Answer:

P max = 1000 pa

P min = 200 pa

Explanation:

P = F/A

pressure will be maximum when surface gets minimum. so to find the maximum amount of pressure we need to calculate the minimum surface. it is 2cm×5cm = 10cm² = 0.001m² . then we have:

P = 1 / 0.001 = 1000 pa

to find minimum pressure the surface that must be chosen is 10cm×5cm = 50cm² = 0.005m² .

P = 1 / 0.005 = 200 pa

7 0
2 years ago
Solve for y<br>11=y/3+7​
butalik [34]

Answer:

Explanation:

11 = y/3+7

collecting like terms

11 - 7 = y/3

4 = y/3

multiplying both sides by 3 gives us

12 = y

therefore

y = 12

3 0
3 years ago
Denise is conducting a physics experiment to measure the acceleration of a falling object when it slows down and comes to a stop
Butoxors [25]

Answer:

D!

Explanation:

Using the formula F = ma, you plug in 4.9 for F (force), and 0.5 for m (mass), then solve for a (acceleration).

4 0
4 years ago
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