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MatroZZZ [7]
2 years ago
15

A rectangular box has side 10cm x 5cm x 2cm. If it lies on a horizontal surface and has weight 1.00N, calculate the maximum and

Minimum pressure it exerts on the Surface
​
Physics
1 answer:
Vladimir [108]2 years ago
7 0

Answer:

P max = 1000 pa

P min = 200 pa

Explanation:

P = F/A

pressure will be maximum when surface gets minimum. so to find the maximum amount of pressure we need to calculate the minimum surface. it is 2cm×5cm = 10cm² = 0.001m² . then we have:

P = 1 / 0.001 = 1000 pa

to find minimum pressure the surface that must be chosen is 10cm×5cm = 50cm² = 0.005m² .

P = 1 / 0.005 = 200 pa

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(a) 89 m/s

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(b) The tension, T, is given by

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The cable is approximately a cylinder with diameter 1.5 cm and length or height of 620 m. Its volume is

V = \pi \dfrac{d^{2}}{4} l

T = \dfrac{\rho\cdot\pi d^2 l}{4l}v^2 = \dfrac{\rho\cdot\pi d^2}{4}v^2

T = \dfrac{8050\times\pi\times0.015^2}{4} \times 88.57^2

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