Answer:
The surface charge density on planes A and B respectively is
and
Explanation:
From the question we are told that
The electric field in region to the left of A is
The direction of the electric field is left
The electric field in the region to the right of B is
The direction of the electric field is right
The electric field in the region between the two planes is
The direction of the electric field is right
Let the surface charge density on planes A and B be represented as
From the question we see that
Generally the electric to the right and to the left is due to the combined electric field generated by plane A and B so
=>
Generally the electric field at the middle of the plane A and B is due to the diffencence in electric field generated by plane A and B
i.e
=>
=>
From equation 1
=>
So
=>
Answer:1. Increase 2. Decrease 3. Decrease
Explanation:
Answer:
The new pressure is 4 times of the initial pressure.
Explanation:
Given that,
The pressure of an ideal gas is 4 atm.
We need to find the change in the pressure of the gas if the temperature by a factor of 4.
We know that,
PV = nKT ....(1)
P = pressure, V = volume, T = temperature
Let P' is the new pressure of the gas. So,
P'V= nK(4T) ......(2)
Dividing equation (1) and (2) we get :
It means that the new pressure is 4 times of the initial pressure.