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MatroZZZ [7]
2 years ago
15

A rectangular box has side 10cm x 5cm x 2cm. If it lies on a horizontal surface and has weight 1.00N, calculate the maximum and

Minimum pressure it exerts on the Surface
​
Physics
1 answer:
Vladimir [108]2 years ago
7 0

Answer:

P max = 1000 pa

P min = 200 pa

Explanation:

P = F/A

pressure will be maximum when surface gets minimum. so to find the maximum amount of pressure we need to calculate the minimum surface. it is 2cm×5cm = 10cm² = 0.001m² . then we have:

P = 1 / 0.001 = 1000 pa

to find minimum pressure the surface that must be chosen is 10cm×5cm = 50cm² = 0.005m² .

P = 1 / 0.005 = 200 pa

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6) b) 2.7 m/s

7) b) DCA

8) b) B

Explanation:

6)

In a displacement-time plot, the slope of the line is given by

m=\frac{\Delta y}{\Delta x}

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\Delta y is the change in the y-variable, so it is the displacement

\Delta x is the change in the x-variable, so it is the time elapsed

So, the slope of the line in a displacement-time plot corresponds to the velocity:

v=m=\frac{d}{t}

Therefore, to find the velocity of the object, we have to estimate the slope of its curve.

To estimate the velocity of object B, we have to estimate the slope of the line tangent to curve B at 10 seconds.

By doing an estimate by eye, we see that the displacement of object B changes from -10 m to 0 m when time increases from about 8 s to 12 s, so the velocity is about:

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7)

As we said in part A, the velocity of each object is given by the slope of each curve.

Therefore:

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- The less steep the curve, the lower the velocity

From the graph, we observe that, among A, C and D:

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- Curve C is less steep than curve C, so object C has the second largest magnitude of velocity

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b) DCA

8)

In the graph, the overall displacement of each object is given by the change in the y-variable, \Delta y.

This means that the object with largest displacement is the object whose curve has the largest variation in y.

From the graph, we see that:

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\Delta y=30-(-15)=45 m

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Answer:

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