Suppose you wanted to increase the force between two point charges by a factor of 5. By what factor must you change the distance
1 answer:
Answer:
the distance between the two point charges will be reduced by a factor of
Explanation:
The force between two point charges is given by Coulomb's law;
where;
k is Coulomb's constant
Q₁ and Q₂ are two point charges
r is the distance between the two charges
From the equation above, the following relationship between force and distance can be deduced;
F₁r₁² = F₂r₂²
F₁r₁² = (5F₁)r₂²
r₁² = 5r₂²
Thus, the distance between the two point charges will be reduced by a factor of
You might be interested in
The speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Given the data in the question;
Since the brick was initially at rest before it was dropped,
- Initial Velocity;
- Height from which it has dropped;
- Gravitational field strength;
Final speed of brick as it hits the ground;
velocity is simply the same as the speed at which a particle or object moves. It is the rate of change of position of an object or particle with respect to time. As expressed in the Third Equation of Motion:
Where v is final velocity, u is initial velocity, h is its height or distance from ground and g is gravitational field strength.
To determine the speed of the brick as it hits the ground, we substitute our giving values into the expression above.
Therefore, the speed of the brick dropped by the builder as it hits the ground is 17.32m/s.
Learn more about equations of motion: brainly.com/question/18486505