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3 years ago

Explain the relationships between gravity, mass, and distance.

Physics

2 answers:

Mazyrski [523]3 years ago

7 0

Answer:

As the mass of an object increases, its gravitational force increases.

As an object's distance to other objects increases, its gravitational force on those objects increases.

Explanation:

The gravitational force of one object on another is calculated with the equation

F = (G*m1*m2)/(r²),

where G is the gravitational constant,

M1 and M2 are the masses of the two objects, and

r is the distance between them

We can see that the force has a direct relationship with both of the mass values, and an inverse square relationship with the distance between them.

Hope this helped!

dexar [7]3 years ago

7 0

Simpler way to put it:

Gravity has a direct relationship with mass. An increase in mass results in an increase in gravitational force. Gravity also has an inverse relationship with distance. An increase in distance results in a decrease in gravitational force.

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Is mass is 88.2 and height of distance is 25m, how do you find speed?

Natasha_Volkova [10]

Answer:

The velocity will be v = 22.1[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy is converted to kinetic energy. For this problem we will take the point with maximum potential energy when the body is 25 [m] high. By the time the height is zero, the potential energy will have been transformed into kinetic energy, and we can find the velocity of the body.

$Ep = m*g*h\\where:\\m = mass = 88.2[kg]\\h = elevation = 25[m]\\g = gravity = 9.81 [m/s^2]\\Ep = 88.2*25*9.81 = 21631.05[J]\\$

Now we know that the energy will be transformed.

$Ek=Ep\\Ek=0.5*m*v^{2} \\where:\\v=velocity [m/s]\\v=\sqrt{\frac{Ek}{0.5*m} } \\v=\sqrt{\frac{21631.05}{0.5*88.2} } \\v=22.14[m/s]$

4 0

2 years ago

Need some help with these two physics problems!

Juliette [100K]

The force that keeps the puck moving is 0.25 N while the velocity of the puck is 3.7 m/s.

<h3>What is the centripetal force?</h3>

We know that the centripetal force is the force that acts on a body that is moving along a circular path. In this case, we are told that the puck is moving along a circular path hence it is acted upon by the centripetal force that acts on it.

The centripetal force in this case would be supplied by the weight of the object that is moving in the circular path. Thus we can write in our equation that;

Centripetal force = Weight of object = mg

m = mass of the object

g = acceleration due to gravity

Then;

W = 0.026 Kg * 9.8 m/s^2

W = 0.25 N

To obtain the velocity of the object;

FT = mv^2/r

v = √ FT r/m

v = √0.25 * 1.4/0.026

v = 3.7 m/s

Learn more about centripetal force:brainly.com/question/11324711

#SPJ1

5 0

1 year ago

A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 800.0 N on him. Th

ipn [44]

Answer:

a) $F_{fric}$ = 692 N

b) $F_{applied}$ = 932 N

Explanation:

According to newton's second law of motion, acceleration of an object is directly proportional to the net force acting on it. When there is no net force force acting on the body, there is no acceleration. A force is a push or a pull, and the net force ΣF is the total force, or sum of the forces exerted on an object in all directions.

$F_{net}$ ∝ a

$F_{net}$ = ma

$F_{applied} - F_{fric}$ = ma

Given data:

$F_{applied}$ = 800 N

Mass = m = 90 kg

acceleration = a = 1.2 m/s²

$F_{fric}$ = ?

800 - $F_{fric}$ = (90)(1.2)

$F_{fric}$ = 692 N

According to newton's second law of motion,

$F_{net}$ ∝ a

$F_{net}$ = ma

$F_{applied} - F_{fric}$ = ma

Given data:

If we assume the same friction and acceleration between player's feet and ground as calculated in part a

$F_{fric}$ = 692 N

acceleration = a = 1.2 m/s²

We take the equal mass to the total mass of both the players because when the winning player push losing player backward, he exert force on the ground not only due to his mass but also due to the mass of losing player.

Mass = M = m₁ + m₂ = 110 kg + 90 kg

= 200 kg

$F_{applied}$ = ?

$F_{applied}$ - 692 N = (200)(1.2)

$F_{applied}$ = 692 + 240

$F_{applied}$ = 932 N

7 0

3 years ago

A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object?

hichkok12 [17]

Hello!

A force of 5 N produces an acceleration of 2 m/s2 on the object. What is the mass of the object ?