Answer:
It would be the brick since the mass and the weight is greater than the peanut I might be wrong on this but thats the best answer i can give
Explanation:
Explanation:
We have,
The initial position of an object is zero.
The starting velocity is 3 m/s and the final velocity was 10 m/s.
The object moves with constant acceleration..
The area covered under the velocity-time graph gives displacement of the object. The correct option is "the area of the rectangle plus the area of the triangle under the line".
Respuesta: verifique amablemente la explicación
Explicación:
Dado lo siguiente:
Longitud (L) del cable = 120 m
Diámetro (d) = 2,2 mm (2,2 / 1000) = 2,2 * 10 ^ -3 m
Fuerza (F) = 380 N
Esfuerzo longitudinal = Fuerza / Área
Área = πd² / 4 = (π * (2.2 * 10 ^ -3) ^ 2) / 4
Área = (3.142 * 4.84 * 10 ^ -6)
Área = 0.00000380132 m²
Estrés = Fuerza / Área
Estrés = 380 / 0.00000380132
Esfuerzo longitudinal = 99952128.12 = 9.9952128 * 10^7 Nm^-2
Deformación longitudinal: extensión / longitud
Extensión = 0.10 m
Longitud = 120 m
Deformación longitudinal = 0,1 m / 120 m
Deformación longitudinal = 0.0008333 = 8.33 × 10 ^ -4
A scientific law is the simple mathematical expression of the relationship involved. A principle is the same relationship expressed in words. A theory is the explanation of the facts that make up the relationship.
Answer:
A) 1568.60 Hz
B) 1437.15 Hz
Explanation:
This change is frequency happens due to doppler effect
The Doppler effect is the change in frequency of a wave in relation to an observer who is moving relative to the wave source

where
C = the propagation speed of waves in the medium;
Vr= is the speed of the receiver relative to the medium,(added to C, if the receiver is moving towards the source, subtracted if the receiver is moving away from the source;
Vs= the speed of the source relative to the medium, added to C, if the source is moving away from the receiver, subtracted if the source is moving towards the receiver.
A) Here the Source is moving towards the receiver(C-Vs)
and the receiver is standing still (Vr=0) therefore the observed frequency should get higher

B)Here the Source is moving away the receiver(C+Vs)
and the receiver is still not moving (Vr=0) therefore the observed frequency should be lesser
