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OleMash [197]
3 years ago
9

Who much force is needed to accelerate a 68 kilogram-skier at a Rate of 1.2 m/sec

Physics
1 answer:
liberstina [14]3 years ago
7 0
If F =m*a
and the question says how much force the s needed to accelerate a 68kg skier to a rate of 1.2ms^-2
Then F = 68*1.2
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Answer:

The magnitude of Force is 8.58×10⁵N and direction is upwards

Explanation:

The work beam does on the pile driver is given by

W=(FCos180°)Δx= -F(0.088m)

From work energy theorem

W_{nc}=(KE_{f}-KE_{i})+(PE_{f}-PE_{i})\\W_{nc}=1/2m(vf^{2}-vi^{2})+mg(yf-yi)

Choosing y=0 at the the level where the driver first contacts the beam and vi=0 at yi=+3.40m and comes to rest again vf=0 at yf= -0.088m

So

-F(0.088m)=1/2m(0-0)+2,200kg(9.81m/s^{2} )(-0.088m-3.40m)\\-F(0.088)=-75508.224\\F=75508.224/0.088\\F=8.58*10^{5} N

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d1i1m1o1n [39]

The average acceleration in 0.67 m/s^2.

The average acceleration is calculated as change in velocity/time

a=(247*5/18)/(1.7*60)

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A fisherman sees his boat moving up and down, owing to waves on the water. It takes 2.5 s for the boat to travel from its highes
nata0808 [166]

Answer:

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v=1.20 \frac{m}{s}

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