Answer:height above ground at which projectile have velocity
0.5v is (0.0375v^2)
Explanation:
Using Vf = Vi - gt
Where Vf is final velocity
Vi is initial velocity
g is the acceleration due to gravity
t is the time taken
So, 0.5v = v - gt
t = 0.05v
Therefore height h = vt - 0.5gt^2
Subtitute t
h = 0.05v^2 - 0.0125v^2
h = 0.0375v^2
Answer:
that is the definition of work
Explanation:
(1) The difference in pressure between the ends of the pipe is 611 kPa.
(2) The Reynold's number for this torpedo is 1.2 x 10⁷.
(3) The flow of water around the torpedo is turbulent.
<h3>Difference in pressure between the ends of the pipe</h3>
The difference in pressure is calculated by applying Poiseuille formula.

where;
- Q is flow rate
- r is radius of the pipe
- L is length of the pipe
- η is viscosity
- ΔP is change in pressure


<h3>Reynold's number for the torpedo</h3>

<h3>Laminar or turbulent flow </h3>
- A flow is considered laminar if the Reynolds number is up to 2300.
- A flow is considered turbulent if the Reynolds number is greater than 3500.
The calculated Reynold's number (1.2 x 10⁷) is greater than 3500. Thus, the flow is turbulent.
Learn more about turbulent flow here: brainly.com/question/12081428
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