Answer:
No metals. Right side.
Explanation:
On the right. Non metallic elements
Answer:
H-O* + CH3-CH3 ----> H-O-CH2-CH2*
Answer:
I mean ig it is, but i dk
Explanation:
Answer:
1.0190 x 10⁻⁵ mol
Explanation:
We know the titration required 10.19 mL of 0.001000 M KIO₃, from this information we can calculate the number of moles KIO₃ reacted and from there the number of moles of ascorbic acid since it is a monoprotic acid ( 1 equivalent of ascorbic acid to one equivalent KIO₃).
Molarity = mol/V
V KIO₃ = 10.19 mL = 10.19 mL x 1 L/1000 mL = 0.01019 L
⇒ mol KIO₃ = V x M = 0.01019 L x 0.0010 mol / L = 1.0190 x 10⁻⁵ mol KIO₃
# mol ascorbic acid = # mol KIO₃ = 1.0190 x 10⁻⁵ mol
Answer:
the pressure to which this volume of air must be compressed in order to fit into the air tank is 28.5478 atm
Explanation:
the solution is attached in the Word file
