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3 years ago

How many grams of sodium are needed to produce 12.5g of sodium oxide

Chemistry

1 answer:

Hatshy [7]3 years ago

4 0

Answer:

25 possibly

Explanation:

I'm not too sure about this, but sodium oxide is Na2O, 2 sodium and 1 oxygen, so 12.5g * 2 is 25

If someone else comes up with a more convincing argument listen to them

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(04.02 LC) Based on the cell theory, which of the following is true?

prohojiy [21]

Answer:

Explanation:

there are billions of cells in living things. We are made out of millions of cells

4 0

2 years ago

1) How many molecules are there in 985 mL of nitrogen at 0.0° C and 1.00 x 10-6 mm Hg?

RSB [31]

Answer : The number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

Explanation :

First we have to calculate the moles of nitrogen gas by using ideal gas equation.

$PV=nRT$

where,

P = Pressure of $N_2$ gas = $1.00\times 10^{-6}mmHg=1.32\times 10^{-9}atm$ (1 atm = 760 mmHg)

V = Volume of $N_2$ gas = 985 mL = 0.982 L (1 L = 1000 mL)

n = number of moles $N_2$ = ?

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of $N_2$ gas = $0.0^oC=273+0.0=273K$

Now put all the given values in above equation, we get:

$(1.32\times 10^{-9}atm)\times 0.982L=n\times (0.0821L.atm/mol.K)\times 273K$

$n=5.78\times 10^{-11}mol$

Now we have to calculate the number of molecules present in nitrogen gas.

As we know that 1 mole of substance contains $6.022\times 10^{23}$ number of molecules.

As, 1 mole of $N_2$ gas contains $6.022\times 10^{23}$ number of molecules

So, $5.78\times 10^{-11}$ mole of $N_2$ gas contains $(5.78\times 10^{-11})\times (6.022\times 10^{23})=3.48\times 10^{13}$ number of molecules

Therefore, the number of molecules present in nitrogen gas are, $3.48\times 10^{13}$

8 0

3 years ago

(3 Points)

prisoha [69]

Your answer is B. radio waves have shorter wavelenghts than microwaves.
Have a great day

5 0

3 years ago

Read 2 more answers

A body of mass 5kg has momentum of 125kgm/s. find the velocity of the body in motion.

borishaifa [10]

Explanation:We have momemtum = mass X velocity

p = mv

OR, p/m = v

v = (125kg m/s)25kg

v = 125/25 m/s

v = 5 m/s

8 0

3 years ago

¿A qué se debe la coloración de la llama cuando hay un halógeno presente?

Nimfa-mama [501]

Answer:

Green

Explanation:

Positive: A strong green color in the flame indicates the presence of halogens (chloride, bromide, iodide but not fluoride).

8 0

2 years ago