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attashe74 [19]
3 years ago
6

Use these images to identify each state of matter. O O CC 0 COM A B C​

Physics
1 answer:
Nikolay [14]3 years ago
7 0

Answer:

A=Gas

B= Solid

C=Liquid

Explanation:

A gas has the particles dispersed everywhere

so A is the gas

Liquid and Solid have them more close together

but the solid has them in some order

so as you can see

B is solid

and

C is liquid

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A voltage of 12 cos(I000t+45) Vis applied to a circuit in which a resistor of 4 .n, aninductor of L H, and a capacitor of 100 μF
vlabodo [156]

Answer:

0.01 H

Explanation:

V = 12 cos (1000t + 45)

C = 100 micro farad

Let the inductance be L .

When the current and the voltage are in the same phase so it is the condition of resonance.

So capacitive reactance = inductive reactance

Xc = XL

1/ωC = ωL

L = 1 / ω²C

By comparisonV = Vo Cos (ωt + Ф)

ω = 1000 rad/s

L = 1 / (1000 x 1000 x 100 x 10^-6)

L = 1 / 100

L = 0.01H

thus, the inductance of the inductor is 0.01 H.

8 0
3 years ago
The instantaneous emf resulting from magnetic induction equals the rate of change of flux is
katen-ka-za [31]

Lenz's Law: The polarity of the induced emf is such that it produces a current whose magnetic field opposes the change in magnetic flux through the loop.

7 0
3 years ago
A capacitor with air between its plates ischarged to 60 V and then disconnected fromthe battery. When a piece of glass is placed
-BARSIC- [3]

Answer:

       k = 1.30

Explanation:

For this exercise let's write the capacitance in air and with dielectric

air             C₀ = Q / DV

dielectric  C = k Q / DV

They tell us that the capacitor is charged and then the battery is disconnected, therefore the charge stored on the plate remains constant.

                         

therefore the capacitance a changes to the value

           C = k C₀

The voltage in the presence of dielectric must meet the relationship

           ΔV = ΔV₀ / k

           k = ΔV₀ /ΔV

let's calculate

           k = 60/46

           k = 1.30

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Answer:

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