Answer:
1 m/s²
Explanation:
From the question,
Using
a = (v-u)/t.................... Equation 1
Where a = accelartion of the bicycle, v = Final velocity, u = initial velocity, t = time.
Given: v = 15 m/s, u = 5 m/s, t = 10 s
Substitute these values into equation 1
a = (15-5)/10
a = 10/10
a = 1 m/s²
Hence the acceleration of the bicycle is 1 m/s²
<u>Answer:</u>
<em>The average speed of the car is 66.9 km/h</em>
<u>Explanation:</u>
Here distance covered with the speed <em>57 km/h=7 km </em>
distance covered with the speed of <em>81 km/h=7 km</em>
<em>Average speed is equal to the ratio of total distance to the total time.
</em>
<em>total distance= 7 + 7= 14 km </em>
<em>
</em>
<em>time taken to cover the first 7 km= 7/57 h </em>
<em>time taken to cover the second part of the journey = 7/81 h
</em>
<em>average speed =
</em>
<u><em>Shortcut:
</em></u>
<em>When equal distances are covered with different speeds average speed=2 ab/(a+b) where a and b are the variable speeds in the phases.
</em>
<span>
I think the the answer would be no. </span> If the instantaneous speed of an object remains constant, then its instantaneous velocity would not change. S<span>ince v = c for c is some constant, then |v| = |c|. This is regardless of the sign of c. Hope this answers the question.</span>
Answer:
hm my mom said the net force changes
Answer:
The pressure is constant, and it is P = 150kpa.
the specific volumes are:
initial = 0.062 m^3/kg
final = 0.027 m^3/kg.
Then, the specific work can be written as:

The fact that the work is negative, means that we need to apply work to the air in order to compress it.
Now, to write it in more common units we have that:
1 kPa*m^3 = 1000J.
-5.25 kPa*m^3/kg = -5250 J/kg.