Question

Which of the following is true about Oxygen (O), Sulfur (S) and Neon (Ne)? (Choose 3)

Answer 1

Answer:

Option C, option D and option E is correct

Explanation:

Atomic number of O = 8

Electronic configuration of O = $1s^22s^22p^4$

No. of valence electron = 6

Atomic number of S = 16

Electronic configuration of O = $1s^22s^22p^63s^23p^4$

No. of valence electron = 6

Atomic number of Ne = 10

Electronic configuration of Ne = $1s^22s^22p^6$

No. of valence electron = 8

No. of electron shell present in any atom is equal to principle quantum no.

So, no. of electron shell in O = 2

no. of electron shell in S = 3

no. of electron shell in Ne = 2

O is present in period 2 and group 16.

S is present in period 3 and group 16.

Ne is present in period 2 and group 16.

So, O and S are present in same group. Elements of same group or family display similar chemical properties.

So, among correct options are:

option C: Oxygen and Neon are in the same period and have the same number of electron shells.

Option D: Oxygen and Sulfur have the same number of valence electrons.

Option E: Oxygen and Sulfur are most similar because they are in the same family and have similar chemical properties.

Answer 2

Answer:

from the way I understand the question I think the answer is (B)

Explanation:

Because the distribution into shells of oxygen is 2,6 and in sulfur is 2,8,6 and oxygen has a 8th number of electrons and sulfur has the 16th number of electrons