Answer:
The molar solubility of SrCO3 will be lower in 0.10 M 0 M Sr(NO3)2 because of Sr2+
Explanation:
The question reflects the phenomenon known in chemistry as common ion effect. Common ion effect refers to the decreased solubility of a solid in a solution that contains an ion in common with the solute.
In the case of our example here, both strontium carbonate and strontium nitrate possess the strontium II ion in common. The presence of this ion in strontium nitrate will decrease the solubility of strontium carbonate in accordance with Le Chateliers principle. Hence the answer.
Note down the formula below
Mass of the compound
Mass % of Hydrogen:-
Mass % of Oxygen:-
Answer:
B
Explanation:
Firstly, we will need to calculate the number of moles. To do this, we make use of the ideal gas equation
PV = nRT
n = PV/RT
The parameters have the following values according to the question:
P = 780mmHg, we convert this to pascal.
760mHG = 101325pa
780mmHg = xpa
x = (780 * 101325)/760 = 103,991 Pa
V= 400ml = 0.4L
T = 135C = 135 + 273.15 = 408.15K
n = ?
R = 8314.463LPa/K.mol
Substituting these values into the equation yields the following:
n = (103991 * 0.4)/(8314.463 * 408.15)
= 0.012 moles
Now we know 1 mole contains 6.02 * 10^23 molecules, hence, 0.012moles will contain = 0.012 * 6.02 * 10^23 = 7.38 * 10^21 molecules
Answer: The sample absorbed 3061.565J
Explanation:
Given that
Mass of water = 335g
Initial temperature = 24.5°C
Final temperature = 26.4°C
Heat absorbed by the sample is given as = mass x specific heat of water x temperature change
Heat absorbed,q=mCΔt
The specific heat of water,C = 4.81J/g°C
Therefore, Heat absorbed,q = 335 x 4.81h x (26.4 - 24.5) = 3061.565J
