on the surface of theearth ,the weight of a boy is 400N but on a mountainpeak his weight is 360N,Calculatethe value of ''g' on t
1 answer:
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Hey there,
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Let's get one thing out the way, (wavelength) does
affect the the speed of water. If anything, it would be how high the wavelength's are. The higher the wavelengths are, the more that it would affect the speed, because there very high, but if it were to go longer on the width side, that would increase the speed, but that's not the case. Your correct answer would be (higher wavelength).
Hope this really helps you.
Your question states: What factors affect the speed of water waves
Let's get one thing out the way, (wavelength) does
Hope this really helps you.
Answer:
T = 480.2N
Explanation:
In order to find the required force, you take into account that the sum of forces must be equal to zero if the object has a constant speed.
The forces on the boxes are:
(1)
T: tension of the rope
M: mass of the boxes 0= 49kg
g: gravitational acceleration = 9.8m/s^2
The pulley is frictionless, then, you can assume that the tension of the rope T, is equal to the force that the woman makes.
By using the equation (1) you obtain:
The woman needs to pull the rope at 480.2N
Answer:
1) A
2) C
3) B
4) A
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8) A
9) C
10) C
Explanation:
1) m = 15kg, a = , F = ma = 15*10 = 150N
2) m = 3kg, v = , r = 4m, F =
= 12N
3) a = , r = 10m, v=?
F = and F = ma
equating the two equations and cancelling a, we have:
= a
making v the subject of formula, we have:
v =
=
= 10
4) r = 10m, v = , a = ?
F =
F = ma
equating the above equations and making a subject of formula, we get:
a =
a = 25/10 = 2.5
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8) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is tripled
F =
F = 9
We can see that the force will be 9X greater than it was.
9) F =
assuming m and r is unity, that is the values are 1 respectively, the formula simplifies to:
F =
Now, if v is doubled
F =
F = 4
We can see that the force will be 4X greater than it was.
10) F =
assuming m and v is unity, that is the values are 1 respectively
F = 1/r
if r is doubled,
F = 1/2 * 1/r
We can see that the force is 1/2 as big as it was