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kolbaska11 [484]
3 years ago
11

What is the percentage of iodine in zinc iodate zn(io3)2

Chemistry
1 answer:
shusha [124]3 years ago
5 0

Answer:

61.131%

This is the percentage of iodine in zinc iodate.

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Which term is used to describe all the habitats around the world?
OlgaM077 [116]

Answer:

ecosystem diversity

Explanation:

hope this helped

5 0
2 years ago
How much heat is required to raise the temperature of 20.0g of ice from-12°C to 0°C?
Vladimir79 [104]

Answer:

https://socratic.org/questions/how-much-heat-is-required-to-convert-5-88-g-of-ice-at-12-0-c-to-water-at-25-0-c-

Explanation:

6 0
3 years ago
Is the equation balanced? Why or why not?
anygoal [31]

Answer:

Yes because the law of conservation of matter is followed. There are equal numbers of atoms of all elements in the

reactants and products.​

Explanation:

A balanced equation conform to the law of conservation of matter. While unbalanced equation suggests that matter has been created or destroyed.

Na3PO4 + 3KOH —> 3NaOH + K3PO4

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reactants and products.

8 0
3 years ago
A 34.0 g piece of metal is heated to 92.0°C then placed in a beaker of water containing 22.0 g of water at 19.0°C. The temperatu
lapo4ka [179]

Answer:

0.1988 J/g°C

Explanation:

-Qmetal = Qwater

Q = mc∆T

Where;

Q = amount of heat

m = mass of substance

c = specific heat of substance

∆T = change in temperature

Hence;

-{mc∆T} of metal = {mc∆T} of water

From the information provided in this question, For water; m= 22.0g, ∆T = (24°C-19°C), c = 4.18J/g°C.

For metal; m= 34.0g, ∆T = (24°C-92°C), c = ?

Note that, the final temperature of water and the metal = 24°C

-{34 × c × (24°C-92°C)} = 22 × 4.18 × (24°C-19°C)

-{34 × c × (-68°C)} = 459.8

-{34 × c × -68} = 459.8

-{-2312c} = 459.8

+2312c = 459.8

c = 459.8/2312

c = 0.1988

The specific heat capacity of the metal is 0.1988 J/g°C

6 0
3 years ago
If an element has two isotopes, what is the atomic mass if one of the isotopes has a mass of 15.000 amu and makes up 5.000% of t
olasank [31]
The atomic mass of element is the weighted average atomic mass of the element with respect to the abundance of the isotopes of that element 
atomic mass is the sum of the products of the mass of isotopes by their percentage abundance 
atomic mass = 15.000 amu x 5.000 % + 16.000 amu x 95.000 % 
                     = 0.7500 + 15.200
atomic mass of element is therefore 15.950
8 0
3 years ago
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