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zlopas [31]
2 years ago
14

Which scale is being described? Water freezes at 32. Water freezes at 0. Water freezes at 273.

Chemistry
1 answer:
Leya [2.2K]2 years ago
7 0

Scale is defined as the measurement of unit ranges, that has been corresponds to the measurements.

The units for the measurement of temperature are given as:

\rm 0^\circ C\;=\;273\;K\;=\;32\;F

<h3>Which scale is used?</h3>

The scale used for the measurement of the freezing is the temperature scale. The temperature is measured in the units of Kelvin, Fahrenheit , and Celsius.

The unit scale for the measurement of freezing of water are

  • Freezes at 32 -  In the Fahrenheit scale
  • Freezes at 0 - In the Celsius scale
  • Freezes at 273 - In the Kelvin scale

Learn more about measurement scale, here:

brainly.com/question/1152255

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A mole of Big Macs stacked would reach from the earth to the moon and back how many times?
OLga [1]
A mol=6.02*10^23
so
distance from earth to moon is 230,100 miles
1 big mac is about 2 inches
1 mile=5280 feet=63360inches

230,100 times 63360=14,579,136,000 inches is distance
6.02 times 10^23 times 2=x times 14,579,136,000
divide both sides by 2
6.02 times 10^23=x times 7,289,568,000
divide both sides by 6.02
10^23=x times 1210891694.35159
divide both sides by  1210891694.35159
825583769024485.8
about 825,583,769,024,486 times

6 0
3 years ago
2.00 L of a gas is collected at 25.0°C and 745.0 mmHg. What is the volume at 760.0 mmHg
Leviafan [203]

1.7960L

Explanation:

the mass of the gas is constant in both instances

pv/T=constant(according to pv=nRT)

745mmHg*2L/298K=760mmHg*v/273K

v=1.7960L

5 0
3 years ago
The correct mathematical expression for finding the molar solubility (s) of calcium phosphate is
GalinKa [24]

Answer is: The molar solubility of calcium phosphate is 108s⁵ = Ksp.

<span> Balanced chemical reaction: Ca</span>₃(PO₄)₂(s) → 3Ca²⁺(aq) + 2PO₄³⁻(aq).<span>
[Ca²</span>⁺] = 3s(Ca₃(PO₄)₂) = 3s.<span>
[PO</span>₄³⁻] = 2s.<span>
Ksp = [Ca²</span>⁺]³ · [PO₄³⁻]².<span>
Ksp = (3s)³ · (2s)².
Ksp = 108s</span>⁵.

s = ⁵√(Ksp ÷ 108).

6 0
3 years ago
When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 27.6 g of carbon were burned in the presence of
In-s [12.5K]

Answer:

The answer to your question is: 101.2 g of CO2

Explanation:

C = 27.6 g

O₂ = 86.5 g   remained 12.9 g

O₂ that reacted = 86.5 - 12.9 = 73.6 g

                     C     + O₂      ⇒        CO₂      The equation is balanced

                    27.6    73.6                 ?

MW               12        32                  44

Rule of three

                        12 g of C------------------  44 g  CO2

                       27.6 g C  ------------------    x

                  x = 27.6(44)/12 = 101.2 g of CO2

                       32 g of O2 ---------------    44 g of CO2

                        73.6 g of O2 ------------      x

                  x = 73.6(44)/32 = 101.2 g of CO2

6 0
3 years ago
How do scientists test their ideas
-Dominant- [34]
I think it’s B not rlly sure
5 0
2 years ago
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