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2 years ago

Which scale is being described? Water freezes at 32. Water freezes at 0. Water freezes at 273.

Chemistry

1 answer:

Leya [2.2K]2 years ago

7 0

Scale is defined as the measurement of unit ranges, that has been corresponds to the measurements.

The units for the measurement of temperature are given as:

$\rm 0^\circ C\;=\;273\;K\;=\;32\;F$

<h3>Which scale is used?</h3>

The scale used for the measurement of the freezing is the temperature scale. The temperature is measured in the units of Kelvin, Fahrenheit , and Celsius.

The unit scale for the measurement of freezing of water are

Freezes at 32 - In the Fahrenheit scale
Freezes at 0 - In the Celsius scale
Freezes at 273 - In the Kelvin scale

Learn more about measurement scale, here:

brainly.com/question/1152255

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Answer: The smallest temperature change is shown by water.

Explanation:

To calculate the heat absorbed or released, we use the equation:

$q=mC\times \Delta T$ ......(1)

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$\Delta T$ = change in temperature

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Option a: 50.0 g Fe, $C_{Fe}=0.449J/g^oC$

We are given:

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Option b: 50.0 g water, $C_{water}=4.18J/g^oC$

We are given:

$m=50.0g\\C_{water}=4.18J/g^oC$

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Option b: 25.0 g Pb, $C_{Pb}=0.128J/g^oC$

We are given:

$m=50.0g\\C_{Pb}=0.128J/g^oC$

Putting values in equation 1, we get:

$200.0J=25.0g\times 0.128J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.128}=62.5^oC$

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Option d: 25.0 g Ag, $C_{Ag}=0.235J/g^oC$

We are given:

$m=25.0g\\C_{Ag}=0.235J/g^oC$

Putting values in equation 1, we get:

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Change in temperature = 34.04°C

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We are given:

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Putting values in equation 1, we get:

$200.0J=25.0g\times 0.79J/g^oC\times \Delta T\\\\\Delta T=\frac{200}{25\times 0.79}=10.13^oC$

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