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3 years ago

How much voltage would be necessary to generate 10 amps of current in a circuit that has 5 ohms of

Physics

2 answers:

Lana71 [14]3 years ago

8 0

$U = R * I \rightarrow U = 10 * 5 = 50 V$

denpristay [2]3 years ago

5 0

Answer:

U = R * I \rightarrow U = 10 * 5 = 50 V

Explanation:

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A e B são dos blocos de massas 3,0 kg e 2,0 kg, respectivamente, que se movimentam juntos sobre uma superficie horizontal e perf

makvit [3.9K]

F = m*a

30 N = (ma + mb) * a

30 = 5*a

a = 6 m/s ^2

F de B em A

30 - F de B,A = ma * a

30 - F de B em A = 3 * 6

30 - 18 = F de B em A

12 = F de B em A

Resposta: 6 m/s^2 e 12N

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2 years ago

I need help quick pls . Its either physical or chemical change !

Trava [24]

Physical, chemical, chemical, physical, I’m pretty sure. Natural things, like you starting to breathe heavier are physical most of the time!!!

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2 years ago

If a machine is doing 500 J of work with 75 watts of power, how long did it take to complete its task?

kompoz [17]

Answer:

time = 6.67secs

Explanation:

power = workdone( energy) / time

therefore :

Time = workdone / power

time = 500 / 75

time = 6.67secs

3 0

2 years ago

Water flowing through a cylindrical pipe suddenly comes to a section of the pipe where the diameter decreases to 86% of its prev

masha68 [24]

Answer:

The speed in the smaller section is $43.2\,\frac{m}{s}$

Explanation:

Assuming all the parts of the pipe are at the same height, we can use continuity equation for incompressible fluids:

$\Delta Q=0$ (1)

With Q the flux of water that is $Av$ with A the cross section area and v the velocity, so by (1):

$A_{2}v_{2}-A_{1}v_{1}=0$

subscript 2 is for the smaller section and 1 for the larger section, solving for $v_{2}$ :

$v_{2}=\frac{A_{1}v_{1}}{A_{2}}$ (2)

The cross section areas of the pipe are:

$A_{1}=\frac{\pi}{4}d_{1}^{2}$

$A_{2}=\frac{\pi}{4}d_{2}^{2}$

but the problem states that the diameter decreases 86% so $d_{2}=0.86d_{1}$ , using this on (2):

$v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\approx1.35v_{1}$

$v_{2}\approx(1.35)(32)\approx43.2\,\frac{m}{s}$

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3 years ago

Daniel and Christopher were on a plane traveling at a velocity of 200 km/hr south for 1,000 km. How long (in hours) was the plan

docker41 [41]

Answer:
5 hours

step-by-step explanation:
very simple just divide 1,000 and 200 to get 5

3 0

2 years ago