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Rasek [7]
3 years ago
9

Please explain if you can.

Physics
1 answer:
Rasek [7]3 years ago
3 0
The above diagram an illustration shows how things can balance each other using torque mechanism..
thus in order to balance the elephant and the Rabit.. accordingly .. you must balance the torque
2. you have to find the length of the other part of the lever's arm
• the torque on the left side of lever's arm is equal to
mg*perpendicular distance which is equal to
500*10*10 = 50000 NM
on the right side you have to obtain the same value of torque which will be
mg*perpendicular distance from the right side of lever's arm
1*10*x = 50000 NM
which comes to 5000 m
thus the total length will be
5000+10 = 5010 m
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Explanation:

6 0
3 years ago
A 10-g bullet moving horizontally with a speed of 2.0 km/s strikes and passes through a 4.0-kg block moving with a speed of 4.2
SVEN [57.7K]

Answer:

K=512J

Explanation:

Since the surface is frictionless, momentum will be conserved. If the bullet of mass m_1 has an initial velocity v_{1i} and a final velocity v_{1f} and the block of mass m_2 has an initial velocity v_{2i} and a final velocity v_{2f} then the initial and final momentum of the system will be:

p_i=m_1v_{1i}+m_2v_{2i}

p_f=m_1v_{1f}+m_2v_{2f}

Since momentum is conserved, p_i=p_f, which means:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}+m_2v_{2f}

We know that the block is brought to rest by the collision, which means v_{2f}=0m/s and leaves us with:

m_1v_{1i}+m_2v_{2i}=m_1v_{1f}

which is the same as:

v_{1f}=\frac{m_1v_{1i}+m_2v_{2i}}{m_1}

Considering the direction the bullet moves initially as the positive one, and writing in S.I., this gives us:

v_{1f}=\frac{(0.01kg)(2000m/s)+(4kg)(-4.2m/s)}{0.01kg}=320m/s

So kinetic energy of the bullet as it emerges from the block will be:

K=\frac{mv^2}{2}=\frac{(0.01kg)(320m/s)^2}{2}=512J

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