Who is the son of thetis and peleus??

Arrange the following aqueous solutions in order of decreasing freezing point: 0.10 m Na3PO4, 0.35 m NaCl, 0.20 m MgCl2, 0.15 m

GarryVolchara [31]

Answer: 0.35 m $NaCl$ > 0.20 m $MgCl_2$ >0.10 m $Na3PO_4$ > 0.15 m $CH_3COOH$ > 0.15 m $C_6H_{12}O_6$

Explanation:

Depression in freezing point:

$T_f^0-T_f=i\times k_b\times m$

where,

$T_f$ = freezing point of solution

$T^o_f$ = freezing point of solvent

$k_f$ = freezing point constant

m = molality

1. For 0.10 m $Na3PO_4$

$Na_3PO_4\rightarrow 3Na^++PO_4^{3-}$

, i= 4 as it is a electrolyte and dissociate to give 4 ions. and concentration of ions will be $4\times 0.10=0.40$

2. For 0.35 m $NaCl$

$NaCl\rightarrow Na^++Cl^-$

, i= 2 as it is a electrolyte and dissociate to give 2 ions. and concentration of ions will be $2\times 0.35=0.70$

3. For 0.20 m $MgCl_2$

$MgCl_2\rightarrow Mg^{2+}+2Cl^-$

, i= 3 as it is a electrolyte and dissociate to give 3 ions. and concentration of ions will be $3\times 0.20=0.60$

4. For 0.15 m $C_6H_{12}O_6$

, i= 1 as it is a non electrolyte and does not dissociate to give ions.

5. For 0.15 m $CH_3COOH$

$CH_3COOH\rightarrow CH_3COO^-+H^+$

, i= 2 as it is a electrolyte and dissociate to give 2 ions and thus have $2\times 0.15=0.30$

As concentration is highest for 0.35 m $NaCl$ , freezing point depression will be highest and thus has lowest freezing point. As concentration is lowest for 0.15 m $C_6H_{12}O_6$ , freezing point depression will be lowest and thus has highest freezing point

8 0

4 years ago

Which of the following elements has the lowest first ionizition energy ?

Hatshy [7]

Answer:

I think Mg is correct I am not sure

5 0

3 years ago

Read 2 more answers

What is a pattern in nature

son4ous [18]

Answer:

Patterns in nature are visible regularities of form found in the natural world. These patterns recur in different contexts and can sometimes be modelled mathematically. Natural patterns include symmetries, trees, spirals, meanders, waves, foams, tessellations, cracks and stripes

Explanation:

8 0

4 years ago

A balloon of helium gas in Alabama has a volume of 22.4 L at 26°C and a 1.03 ATM how big with a balloon get if is transported to

Dimas [21]

Answer:

The final volume of the balloon is = 28.11 L

Explanation:

Initial pressure $P_{1}$ = 1.03 atm = 104.325 K pa

Initial temperature $T_{1}$ = 26 °c = 299 K

Initial volume $V_{1}$ = 22.4 L

Final temperature $T_{2}$ = 22 °c = 295 K

Final pressure $P_{2}$ = 0.81 atm = 82 K pa

We know that

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

Put all the values in above formula we get

$\frac{(104.325)(22.4)}{299} = \frac{(82)(V_{2} )}{295}$

$V_{2}$ = 28.11 L

This is the final volume of the balloon.

8 0

3 years ago

If 294 grams of FeS2 is allowed ti react with 176 grams of O2 according to the following equation how many grams of Fe2O3 are pr

podryga [215]

<span>You must balance your equation correctly.
Here is your answer:

294gFeS2 x 1molFeS2/119.99 x 11mols O2/4mols FeS2--> 6.738mol O2

176gO2 x 1mol O2/32gO2 x 4mols FeS2/11mol FeS2--> 2mols FeS2
Now choose the molecule with the lowest amount (Limiting Reagent)

2molsFeS2 x 2molsFe2O3/4molsFeS2 x 159.7g
159.7g Fe2O3 grams produced.</span>

6 0

3 years ago

Read 2 more answers