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ohaa [14]
3 years ago
6

HELP PLEASE! I have some homework for my 9th grade physical science class and it's due Monday, I already completed 1/2 of it, if

you can answer one or more that'll be really helpful, ty! If a question does not make sense please let me know, each of the pages contain a small paragraph that may be needed to complete the question. (p.s. if u do answer a question, please identify the page it is on and what number it is, tysm)
page 1
3: The symbol for one of the elements is derived from its German name, wolfram. What is the English name for this element?

page 2
1. What limitation is placed on electrons in the Bohr model of the atom?

2. When the light from a gas is passed through a prism, why is there only a certain number of lines rather than a continuous spectrum?

3. How is the series of lines emitted by a gas similar to a fingerprint?

4. Explain how scientists can use the pattern of lines from an unknown gas to identify what elements are contained in the gas?

page 3
1. what is ONE important difference between the Greek theory of atoms and Dalton's atomic theory?

2. what is the significance of the invention of the STM?

3. explain how an STM creates an image of the atoms on the surface of a material
Physics
1 answer:
faltersainse [42]3 years ago
8 0

Page 1: #3

Wolfram is known as Tungsten in English (Tungsten's symbol is a W).

Page 2: #1

I think the limitation is that the electrons in the Bohr model are only in certain energy levels and that they orbit the nucleus.

It's been a while since I was in a physical science class so I'm not sure about the rest but I wish you luck! I hope this helps a little bit!

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Answer:

a)

a = 2 [m/s^2]

b)

a = 1.6 [m/s^2]

c)

xt = 2100 [m]

Explanation:

In order to solve this problem we must use kinematics equations. But first we must identify what kind of movement is being studied.

a)

When the car moves from rest to 40 [m/s] by 20 [s], it has a uniformly accelerated movement, in this way we can calculate the acceleration by means of the following equation:

v_{f} = v_{i}+(a*t)

where:

Vf = final velocity = 40 [m/s]

Vi = initial velocity = 0 (starting from rest)

a = acceleration [m/s^2]

t = time = 20 [s]

40 = 0 + (a*20)

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v_{f} ^{2} =  v_{i} ^{2}+(2*a*x)

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x1 = distance [m]

40^2 = 0 + (2*2*x1)

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Now the car maintains its speed of 40 [m/s] for 30 seconds, we must calculate the distance x2 by means of the following equation, it is important to emphasize that this movement is at a constant speed.

v = x2/t2

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x2 = distance [m]

t2 = 30 [s]

x2 = 40*30

x2 = 1200 [m]

b)

Immediately after a change of speed occurs, such that the previous final speed becomes the initial speed, the new Final speed corresponds to zero, since the car stops completely.

v_{f} = v_{i}-a*t

Note: the negative sign of the equation means that the car is stopping, i.e. slowing down.

0 = 40 - (a *25)

a = 40/25

a = 1.6 [m/s^2]

The distance can be calculates as follows:

v_{f} ^{2}  = v_{i} ^{2} -2*a*x3\\

0 = (40^2) - (2*1.6*x3)

x3 = 500 [m]

c)

Now we sum all the distances calculated:

xt = x1 + x2 + x3

xt = 400 + 1200 + 500

xt = 2100 [m]

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Answer:

1.

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