A 1500 kg car drives around a flat 200-m-diameter circular track at 25m/s. What are the magnitude and direction of the net force
1 answer:
The correct answer to the question is : 9375 N.
CALCULATION:
As per the question, the mass of the car m = 1500 Kg.
The diametre of the circular track D = 200 m.
Hence, the radius of the circular path R =
=
= 100 m.
The velocity of the truck v = 25 m/s.
When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.
Hence, the force acting on the car is centripetal force.
The magnitude of the centripetal force is calculated as -
Force F =
=
= 9375 N. [ANS}
The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.
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Answer: 75,242.9 m/s
Explanation:
from the question we are given the following parameters
mass of Lion (ML) = 169,169 kg
velocity of lion (VL) = 777,377.7 m/s
mass of Gazelle (Mg) = 31,731.7 kg
velocity of Gazelle (Vg) = 63,863.8 kg
mass of Lion and Gazelle (M) = 200,900.7 kg
velocity of Lion and Gazelle (V) = ?
The first figure below shows the motion of the Lion and Gazelle with their direction.
The second diagram shows the motion of the Lion and Gazelle with their directions rearranged to form a right angle triangle.
from the triangle formed we can get the velocity of the Lion and Gazelle immediately after collision using their momentum and Phytaghoras theorem
momentum = mass x velocity
momentum of the Lion = 169,169 x 77,377.3 = 13,089,840,463.7 kgm/s
momentum of the Gazelle = 31,731.7 x 63,863.8 = 2,026,506,942.46 kgm/s
momentum of the Lion and Gazelle = 200,900.7 x V
now applying Phytaghoras theorem we have
13,089,840,463.7 + 2,026,506,942.46 = 200,900.7 x V
15,116,347,406.16 = 200,900.7 x V
V = 75,242.9 m/s
Answer:
steady state temperature =88.7deg C
t=time within 1 deg C of it steady state is 8.31s
Explanation:
A 1 m long wire of diameter 1mm is submerged in an oil bath of temperature 25-degC. The wire has an electrical resistance per unit length of 0.01 Ω/m. If a current of 100 A flows through the wire and the convection coefficient is 500W/m2K, what is the steady state temperature of the wire? From the time the current is applied, how long does it take for the wire to reach a temperature within 1-degC of the steady state value? The density of the wire is 8,000kg/m3, its heat capacity is 500 J/kgK and its thermal condu
The diameter of the wire is known to be=1mm
properties=
The density of the wire is 8,000 kg/m3,
heat capacity is 500 J/kgK
themal conductivity is 20W/m.K
electrical resistance per unit length of 0.01 Ω/m
from lump capavity method
500*(2.5*10^-4)/20
0.006<0.1
we know also, to find steady state temperature
Dh(T-Tinf)=
make T the subject of the equation , we have
T=25+
T=88.7 degC
rate of chnage in temperature
dT/dt=
at t=o and integrating both sides
we have
t=8.31s
steady state temperature =88.7deg C
t=time within 1 degC of it steady stae is 8.31s