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e-lub [12.9K]
3 years ago
15

Help!!!! A loop of area 0.100 m^2 is oriented at 15.5 degree angle to a 0.500 T magnetic field. It rotates until it is at a 45.0

degree angle with the field. What is the resulting change in the magnetic flux?
Physics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

Resulting Change in the Magnetic Flux =0.013\:Wb

Explanation:

Thanks!

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Answer:

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Explanation:

https://en.wikipedia.org/wiki/Astronomical_unit

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Answer:

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Explanation:

(a)

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Therefore,

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m = (2620 kg/m³)(6.138 x 10¹⁷ m³)

<u>m = 1.6 x 10²¹ kg</u>

<u></u>

(b)

The kinetic energy will be:

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Therefore,

K.E = (1/2)(1.6 x 10²¹ kg)(3.17 x 10⁻¹⁰ m/s)²

<u>K.E = 2.536 x 10¹¹ J</u>

<u></u>

(c)

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K.E = (1/2)mv²

2.536 x 10¹¹ J = (1/2)(77 kg)v²

v = √(2)(2.536 x 10¹¹ J)

<u>v = 7.12 x 10⁵ m/s</u>

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