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rewona [7]
3 years ago
5

How do earthquakes affect earths surface?

Physics
1 answer:
ivanzaharov [21]3 years ago
4 0
Some of the reasons that can cause can earthquake are volcanic eruptions, the grinding of tectonic plates beneath the earth's crust and violent explosions which can be artificially induced as well. No matter what the reason is, earthquakes affect the environment and earth's surface. Noticeable cracks have formed on the earth's surface after earthquakes. If the tremors are violent, it can result in the destruction of landscapes. The mountains become prone to land sliding. the glacier's become a threat because of fear of avalanches. tsunamis which are earthquakes in the ocean bed can cause heavy flooding which causes water to cross all boundaries and shores and flood entire cities. Earthquakes caused by volcanoes can result in the spewing of so much lava that it may spill everywhere and cool changing the surface of the earth geologically as well as the ash causing aerial pollution.
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3 years ago
If the sprinter from the previous problem accelerates at that rate for 20 m, and then maintains that velocity for the remainder
kakasveta [241]

Question:

A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?

Answer:

Time for the race will be t = 9.26 s

Explanation:

Given data:

As the sprinter starts the race so initial velocity = v₁ = 0

Distance = s₁ = 20 m

Acceleration = a = 4.20 ms⁻²

Distance = s₂ = 100 m

We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.

Using 3rd equation of motion

(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)

v₂ = 12.96 ms⁻¹

Time for 20 m distance = t₁ = (v₂ - v ₁)/a

t₁ = 12.96/4.2 = 3.09 s

He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be

Time for 100 m distance = t₂ = s₂/v₂

t₂ = 80/12.96 = 6.17 s

Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s

T = 9.26 s

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What is the density of an object that has a mass of 30 g and a volume of 20cm cubed/ to the third power?
Ksenya-84 [330]

Answer:

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datos

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solución

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