A car changes velocity at a constant acceleration of 2.5m/s to reach 43.7m/s in 2.7 s how fast was the car moving when it began to accelerate?
1 answer:
The formula we can use in this case is:
v = v0 + a t
where v is final velocity, v0 is initial velocity, a is
acceleration and t is time
So finding for v0:
v0 = v – a t
v0 = 43.7 – (2.5) 2.7
v0 = 36.95 m/s
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