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allsm [11]
3 years ago
10

If you wanted to know how big a tiger is which measurements would you use?

Chemistry
2 answers:
enot [183]3 years ago
4 0

Answer:

meter kilogram are the two measurement units which can be used to estimate the length and weight of the tiger

Explanation:

In general, measurement units are chosen such that they closely match the object that is to be measured.

In this case, in order to estimate how 'big' the tiger is there are are two units:

-one which measures the length/height of the tiger expressed in units of meter(m)

- the other measures the weight of the tiger which is expressed in units of kilogram (kg)

Elan Coil [88]3 years ago
3 0
I think the answer is
D. Meter Second
hope this helps.
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Caffeine (C8H10N4O2) is a stimulant found in coffees and teas. When dissolved in water, it can accept a proton from a water mole
Olenka [21]

Answer:

See figure 1

Explanation:

If we want to find the acid and the Brønsted-Lowry base, we must remember the definition for each of these molecules:

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3 0
3 years ago
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Answer:

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Explanation:

4 0
3 years ago
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ELEN [110]
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5 0
3 years ago
what is the minimum mass of ethylene glycol that must be dissolved in 14.5 kg of water to prevent the solution from freexing at
lbvjy [14]

Answer:

The minimum mass of ethylene glycol = 6.641 Kg

Explanation:

\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f

Where T_f = freezing point of pure solvent water, 0°C

T_f'= Freezing point of solvent after mixture

K_f = Freezing point depression constant = 1.86 °C/m

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Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g

molality of ethylene glycol

m = \frac{weight}{mol.wt} \times\frac{1000}{V}

Substitute the values to calculate m

m = \frac{w}{60} \times\frac{1000}{14.5\times1000}

by formula

0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}

calculating we get w = 6641.93 g

Therefore, The minimum mass of ethylene glycol = 6.641 Kg

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2 years ago
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3 years ago
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