Which formula can be used to calculate the horizontal displacement not of a horizontally launched projectile

1 answer:

8 0

If you are looking to get an object up the highest, shoot it straight up. If you want to go for a specific horizontal displacement, use the range equation. R = v2sin(twice the launch angle)/ g. g is the gravitaional constant, 9.8 meters per second. Use degrees for the angle. v is the launch velocity. R is the horizontal displacement. This formula only works if your start altitude and end altitude are the same, i.e. you must shoot over a level field. it depends on the gravitational force of attraction of earth and air resistance. if we are neglecting air resistance, the max.horizontal distance is according to this formulae, V0/2 * sin (2theta) where V0 is the initial velocity theta is the angle with x axis and the projection. There are a number of ways that you could find a horizontally displaced object. You could for example just look.

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Un tubo metálico tiene 100 metros de longitud cuando está a 0 oC y 100,13 metros cuando se calienta hasta 100 oC. ¿Cuál es el co

Artyom0805 [142]

Answer:

α= 1.3 10-5 ºC⁻¹

Explanation:

La dilatación termica de los cuerpos esta dada por la relación

ΔL = L₀ α ( T -T₀)

en este caso nos piden el coeficiente de dilatación térmica

α =DL/L₀ DT

calculemos

α = ( 100,13 -100)/[100 (100 – 0)]

α = 1,3 10-5 ºC⁻¹

Traduction

The thermal expansion of bodies is given by the relationship

ΔL = L₀ α (T -T₀)

in this case they ask us for the coefficient of thermal expansion

α = ΔL / L₀ ΔT

let's calculate

α = (100,13 -100) / [100 (100 - 0)]

α= 1.3 10-5 ºC⁻¹

6 0

3 years ago

How far does a car travel in 90 seconds if it’s traveling 55 m/s? Show equation

podryga [215]

You just said the car is traveling at the speed of 55 m/s. If I understand this correctly, that means the car will cover:

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55 meters in the 2nd second,

55 meters in the 3rd second,

55 meters in the 4th second,

55 meters in the 5th second,

55 meters in the 87th second,

55 meters in the 88th second,

55 meters in the 89th second, and

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That's 55 meters 90 times. If you just move these words around a little bit, it says "90 times 55 meters" . . . a pretty simple arithmetic problem.

The equation is . . . Distance = (55 m/s) times (time, in seconds) .

I get 4,953 meters. You should check me on this.

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Klio2033 [76]

Answer:

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Explanation:

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