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Afina-wow [57]
3 years ago
10

A boy exerts a 36-N horizontal force as he pulls a 52-N sled across a cement sidewalk at a constant speed. What is the coefficie

nt of kinetic friction between the sidewalk and the metal sled runners? Ignore air resistance.
Physics
2 answers:
Vesna [10]3 years ago
7 0

Answer:

0.69

Explanation:

Sum of the forces on the sled in the y direction:

∑F = ma

Fn - 52 N = 0

Fn = 52 N

Sum of the forces on the sled in the x direction:

∑F = ma

36 N - Fn μ = 0

Fn μ = 36 N

μ = 36 N / Fn

Substitute:

μ = 36 N / 52 N

μ = 0.69

kupik [55]3 years ago
6 0

Answer:

cofficient of kinetic friction is 0.6923

Explanation:

Given Data

Coefficient of kinetic friction  μk = f_{k}/N where fk is force of kinetic friction and N is normal reaction;

we have N = 52 N, and fk = 36 N ;

                μk = f_{k}/N

                      = 36/52

                      = 0.6923

    cofficient of kinetic friction is 0.6923.

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(b) The net work done on the crate while it is on the rough surface is 23.7 J.

(c) The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.

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v² = 0.845² + 2(-0.396)(0.65)

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The net work done on the crate while it is on the rough surface is 23.7 J.

The speed of the crate when it reaches the end of the rough surface is 0.45 m/s.

Learn more about work done here: brainly.com/question/8119756

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