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Afina-wow [57]
3 years ago
10

A boy exerts a 36-N horizontal force as he pulls a 52-N sled across a cement sidewalk at a constant speed. What is the coefficie

nt of kinetic friction between the sidewalk and the metal sled runners? Ignore air resistance.
Physics
2 answers:
Vesna [10]3 years ago
7 0

Answer:

0.69

Explanation:

Sum of the forces on the sled in the y direction:

∑F = ma

Fn - 52 N = 0

Fn = 52 N

Sum of the forces on the sled in the x direction:

∑F = ma

36 N - Fn μ = 0

Fn μ = 36 N

μ = 36 N / Fn

Substitute:

μ = 36 N / 52 N

μ = 0.69

kupik [55]3 years ago
6 0

Answer:

cofficient of kinetic friction is 0.6923

Explanation:

Given Data

Coefficient of kinetic friction  μk = f_{k}/N where fk is force of kinetic friction and N is normal reaction;

we have N = 52 N, and fk = 36 N ;

                μk = f_{k}/N

                      = 36/52

                      = 0.6923

    cofficient of kinetic friction is 0.6923.

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6 0
3 years ago
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How does a battery produce an electric current in a circuit ?
Elza [17]

Answer:

A battery is a device that stores chemical energy and converts it to electrical energy. The chemical reactions in a battery involve the flow of electrons from one material to another, through an external circuit. The flow of electrons provides an electric current that can be used to do work.

5 0
3 years ago
A system has 4 independent and identical motors, in order for the system to work, at least one of the motors must operate. Each
grin007 [14]

Answer:

The system's Mean Time to Failure is 1,041.\bar 6 hours

Explanation:

The number of independent identical motors = 4

The failure rate of each motor, λ = 0.002 failures per hour

Given that in order for the system to work, at least one of the motors must operate, therefore, the system are in parallel

The Mean Time to Failure for a parallel system of four identical components is given as follows;

MTTF = \dfrac{1 }{\lambda} \times \left (1 + \dfrac{1}{2} +  \dfrac{1}{3} + \dfrac{1}{4} \right)

Which gives;

MTTF = \dfrac{1 }{0.002} \times \left (1 + \dfrac{1}{2} +  \dfrac{1}{3} + \dfrac{1}{4} \right) = 1,041.\bar 6

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8 0
3 years ago
A box rests on a horizontal, frictionless surface. a girl pushes on the box with a force of 17 n to the right and a boy pushes o
Komok [63]
Refer to the diagram shown below.

The net force acting on the box is 17 - 13 = 4 N to the right.
The box moves on a friction surface by 3.5 m to the right.

By definition,
Work = Force x Distance.

(a) The work done by the girl is
     W₁ = (17 N)*(3.5 m) = 59.5 J

(b) The work done by the boy is
     W₂ = (13 N)*(-3.5 m) = - 45.5 J

(c) The work done by the net force  is
    W₃ = (4 N)*(3.5 m) = 14 J

Note that W₃ = W₁ + W₂

Answers:
(a) 59.5 J
(b) - 45.5 J
(c) 14 J

5 0
4 years ago
with what speed does a freely falling object dropped from a height of 88.2m hit the ground? how long does it take for it hit the
maria [59]

Answer:

Vf = 41.6 [m/s]

Explanation:

To solve this problem we must use the equations of kinematics.

Vf² = Vo² + (2*g*y)

where:

Vf =  final velocity [m/s]

Vo = initial velocity = 0

g = gravity acceleration = 9.81 [m/s²]

y = height = 88.2 [m]

Note: The positive sign of the equation tells us that the acceleration of gravity goes in the direction of motion.

Vf² = Vo² + (2*g*y)

Vf² = 0 + (2*9.81*88.2)

Vf = (1730.48)^0.5

Vf = 41.6 [m/s]

6 0
3 years ago
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