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aleksandr82 [10.1K]
3 years ago
12

Select all that apply.

Chemistry
2 answers:
DIA [1.3K]3 years ago
7 0

Explanation:

Ground water is defined as the water present below the ground. When chemicals spill from factories, industries etc then they are absorbed by soil from where it flows through the pores present in it.

Pesticides and fertilizers also contain toxic substances which flow and absorbed by the ground when it rains.

Hence, they also contribute to water pollution.

Thus, we can conclude that ground water pollution can be caused by chemical spills, pesticides and fertilizers.

Vesna [10]3 years ago
3 0
Select them all.
It's All of the above.
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Convert 685K to Fahrenheit
joja [24]

773.33 degrees F
F=Fahrenheit
K=Kelvin
F=K x 9/5 - 459.67
773.33 = 685 x 9/5 - 459.67

8 0
4 years ago
Which of the elements shown will not form ions, and why will they not do so?
grigory [225]

No elements visible!

Ions form between metals and non-metals.

Hope this helps!

6 0
2 years ago
8moles of Na2Cr2O2 is how much mass​
Margaret [11]

\boxed{\boxed{\mathfrak{ 1\: mole \:of \:Na_2Cr_2O_2\: = \:it's \:Gram\: Mol. \: mass}} }

\underline{ \mathfrak{ Gram \:molecular \:mass \:of \: \red{ Na_2Cr_2O_2}}}

= 2 × 23 + 2 × 52 + 2 × 16

= 182 grams

1 mole of Na_2Cr_2O_2 weighs = 182 g

8 moles weigh = 8× 182

=\mathfrak{\blue {\boxed{\underline {1456 \: grams}}}}

or

\mathfrak{\blue {\boxed{\underline {1. 46 \:kg }}}}

5 0
3 years ago
Great Sand Dunes National Park in Colorado is famous for its giant sand dunes. Sand dunes are landforms that are found in desert
Anit [1.1K]
Either b or c :), i’m not quite sure
5 0
3 years ago
2. The density of helium is 1.78 X 104 g/cm. What is this<br> density in Dg/um??
Zepler [3.9K]

Answer:

d=1.78\times 10^{-7}\ Dg/\mu m^3

Explanation:

Given,

The density of Helium is 1.78\times 10^4\ g/cm^3

We need to find the density in Dg/μm

We know that,

1 g = 10 dg

1 cm³ = 10¹² μm³

So,

d=1.78 \times 10^4\ g/cm^3\\\\=1.78 \times 10^4\times \dfrac{10\ dg}{10^{12}\ \mu m^3}\\\\=1.78\times 10^{-7}\ Dg/\mu m^3

So, the density of Helium is equal to 1.78\times 10^{-7}\ Dg/\mu m^3.

4 0
3 years ago
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