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3 years ago

Select all that apply.

Chemistry

2 answers:

DIA [1.3K]3 years ago

7 0

Explanation:

Ground water is defined as the water present below the ground. When chemicals spill from factories, industries etc then they are absorbed by soil from where it flows through the pores present in it.

Pesticides and fertilizers also contain toxic substances which flow and absorbed by the ground when it rains.

Hence, they also contribute to water pollution.

Thus, we can conclude that ground water pollution can be caused by chemical spills, pesticides and fertilizers.

Vesna [10]3 years ago

3 0

Select them all.
It's All of the above.

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Which of the following are nonelectrolytes? Hc2h302 (acetic acid) CH30H (method alcohol) h2So4 and c12h22011 (sucrose or table s

hoa [83]

Answer:

C₁₂H₂₂O₁₁ and CH₃OH

Explanation:

Sucrose and methyl alcohol are nonelectrolytes. They do not ionize or conduct a current in aqueous solution.

HC₂H₃O₂ is a weak electrolyte. It produces only a few ions and is a poor conductor of electricity in aqueous solution.

HC₂H₃O₂ + H₂O ⇌ H₃O⁺ + C₂H₃O₂⁻

H₂SO₄ is a strong electrolyte. Its first ionization is complete, so it is a good conductor of electricity in aqueous solution.

H₂SO₄ + H₂O ⟶ H₃O⁺ + HSO₄⁻

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3 years ago

Write a balanced half-reaction describing the oxidation of solid chromium to aqueous chromium(IV) cations.

Pachacha [2.7K]

Answer:

Cr(s) ⟶ Cr⁴⁺(aq) + 4e⁻

Explanation:

1. Write the skeleton half-reaction

Cr(s) ⟶ Cr⁴⁺(aq)

2. Balance charge

Add electrons to the side that needs them.

You have 4+ on the right and 0 on the left. You must add 4e⁻ to the right to balance the charge.

Cr(s) ⟶ Cr⁴⁺(aq) + 4e⁻

7 0

3 years ago

Which of the following statements is true?

Fittoniya [83]

Answer:

Es la tercera por qué cuando el material varía va cambiando de estado

Explanation:

8 0

2 years ago

I have two solutions. In the first solution, 1.0 moles of sodium chloride is dissolved to make 1.0 liters of solution. In the se

charle [14.2K]

i not sure but I think yes

6 0

2 years ago

The equilibrium constant Kp for the reaction (CH3),CCI (g) = (CH3),C=CH, (g) + HCl (g) is 3.45 at 500. K. (5.00 x 10K) Calculate

Karolina [17]

<u>Answer:</u> The value of $K_p$ for the reaction is 6.32 and concentrations of $(CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl$ is 0.094 M, 0.094 M and 0.106 M respectively.

<u>Explanation:</u>

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

where,

$K_p$ = equilibrium constant in terms of partial pressure = 3.45

$K_c$ = equilibrium constant in terms of concentration = ?

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = 500 K

$\Delta n_g$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-1=1$

Putting values in above equation, we get:

$3.45=K_c\times (0.0821\times 500)^{1}\\\\K_c=\frac{3.45}{0.0821\times 500}=0.084$

The equation used to calculate concentration of a solution is:

$\text{Molarity}=\frac{\text{Moles}}{\text{Volume (in L)}}$

Initial moles of $(CH_3)_3CCl(g)$ = 1.00 mol

Volume of the flask = 5.00 L

So, $\text{Concentration of }(CH_3)_3CCl=\frac{1.00mol}{5.00L}=0.2M$

For the given chemical reaction:

$(CH_3)_3CCl(g)\rightarrow (CH_3)_2C=CH(g)+HCl(g)$

Initial: 0.2 - -

At Eqllm: 0.2 - x x x

The expression of $K_c$ for above reaction follows:

$K_c=\frac{[(CH_3)_2C=CH]\times [HCl]}{[(CH_3)_3CCl]}$

Putting values in above equation, we get:

$0.084=\frac{x\times x}{0.2-x}\\\\x^2+0.084x-0.0168=0\\\\x=0.094,-0.178$

Negative value of 'x' is neglected because initial concentration cannot be more than the given concentration

Calculating the concentration of reactants and products:

$[(CH_3)_2C=CH]=x=0.094M$

$[HCl]=x=0.094M$

$[(CH_3)_3CCl]=(0.2-x)=(0.2-0.094)=0.106M$

Hence, the value of $K_p$ for the reaction is 6.32 and concentrations of $(CH_3)_2C=CH,HCl\text{ and }(CH_3)_3CCl$ is 0.094 M, 0.094 M and 0.106 M respectively.

8 0

3 years ago