The slope of the line whose equation is 3x - 2y = 4 is 2/3 3/2 -2

1 answer:

alexandr1967 [171]2 years ago

4 0

Solve for "y" and you get y=3x/2-2 and the equation for a line is y= mx+b, I mean the slope is the number which companion the "x" in the line equation, so the slope in your problem is 3/2

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$-2x^2-3x+4=0\\\\a=-2\,,\ b=-3\,,\ c=4\\\\\\x=\dfrac{-b-\sqrt{b^2\pm4ac}}{2a}=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(-2)(4)}}{2(-1)}=\dfrac{3\pm\sqrt{9+32}}{-2}\\\\\\x_1=-\dfrac{3+\sqrt{41}}{2}\approx-4.7\ ,\qquad x_2=-\dfrac{3-\sqrt{41}}{2}\approx1.7$

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