Answer:
the mass of the reactants must equal the mass of product
1.70 billion seconds older than i am now
Potential energy = mgh
So, energy gained
= mgh
= 70kg × (9.8m/s²) × 1000m
= 686000 kgm²/s²
= 686000 J
Answer:
- de Broglie wavelength of the bullet is 4.56 x 10⁻³⁴ m
- The value of the wavelength shows that wave nature of matter is insignificant for the bullet because it is larger than particles.
Explanation:
Given;
mass of the bullet, m = 1.9 g = 0.0019 kg
velocity of the bullet, v = 765 m/s
de Broglie wavelength of the bullet is given by;
where;
h is Planck's constant = 6.626 x 10⁻³⁴ J/s
λ is de Broglie wavelength of the bullet
Thus, this value of the wavelength shows that wave nature of matter is insignificant for the bullet because it is larger than particles.
The Answer is= 7.8 x 10^4