Answer:
The units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.
Explanation:
P² = a³ is the simplified version of Kepler's third law which governs the orbital motion of large bodies that orbit around a star. The orbit of each planet is an ellipse with the star at the focal point.
Therefore, if you square the year of each planet and divide it by the distance that it is from the star, you will get the same number for all the other planets.
Thus, the units of the orbital period P is <em>years </em> and the units of the semimajor axis a is <em>astronomical units</em>.
2/5 = .4
.4*100= 40%
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Two neutral objects will not have any electric force of attraction or repulsion between them.
<h3>What is the condition for the electric force between two objects?</h3>
As we know from the electrostatics that whenever there are two charges having a positive charge on one and a negative on the other will attract each other
similarly, if they are having like charges which are both of them having positive or both of them having a negative charge then there will be a force of repulsion between them.
But if both of them or even one of them is neutral then there will not be any electric force between them.
Thus neutral objects will not have any electric force of attraction or repulsion between them.
To know more about the nature of charged particles follow
brainly.com/question/22492496
Answer:
45 m / s North is a valid vector reading for an object.
Explanation:
Then velocity will be defined by x km / hr North. And, magnitude of velocity defines the speed of the body. Although this tells the speed, but there is no description for the direction, so it's not a vector reading
Answer:
a = 0.1962 m/s^2
Explanation:
The magnitude of kinetic friction exerted is given by
Where, μ_k= coefficient of kinetic friction= 0.02 and N = reaction force = mg
Where m= mass = 30 Kg and, g is acceleration due to gravity =9.81 m/s^2
F_k=0.02×30×9.81 =5.886 N
Now, since, there is no applied force this kinetic friction force will cause acceleration of the child
⇒ ma = F_k
here, a is the acceleration
⇒30a = 5.886
⇒ a = 0.1962 m/s^2
