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MA_775_DIABLO [31]
3 years ago
9

Given f(x)=2x^2+9x+k, and the remainder when f(x) is divided x+7 is 32, then what is the value of k?

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
6 0

Set up either long division or synthetic div.  I'd do the latter.

Your divisor for synth. div. should be -7.

                           __________  
Then              -7 /  2      9      k
                                    -14   +35
                          --------------------
                             2      -5      k+35                 Rem is 32; 
                                                                     Let 32 = k + 5 and solve for k:

                                                                           k = -3.

Let's check that.  Is k correct?

Then              -7 /  2      9      -3
                                    -14   +35
                          --------------------
                             2      -5      -3+35  = 32

Since the rem is 32, we are correct; k = -3.  
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What is the value of n
klasskru [66]

Answer:

9 + 18 = 27

27 + n + 1

= n = 27 - 1 = 26.

n = 26

9 + 18 + 26 + n + 7 =

53 + n + 7

53 + 7 + n

60 + n = 360

n = 360 - 60 = 300

so, n 300

so = 9, 18, 300, 26

7 0
3 years ago
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pickupchik [31]

Answer:

\boxed{ \bold{ \boxed{ \sf{(3m - 4)(9 {m}^{2}  + 12m + 16)}}}}

Step-by-step explanation:

\sf{27 {m}^{3}  - 64}

\dashrightarrow{ \sf{( {3m)}^{3}  -  {(4)}^{3} }}

Use the formula of a³ - b³ = ( a - b) ( a² + ab + b² )

\longrightarrow{ \sf{(3m - 4)(3 {m}^{2}  + 3m \times 4 +  {4}^{2} }})

\longrightarrow{ \sf{(3m - 4)( {9m}^{2}  + 12m + 16}})

Hope I helped!

Best regards! :D

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Can someone please help ty!
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Answer:

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Step-by-step explanation:

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The correct answer is
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