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uranmaximum [27]
2 years ago
5

You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.

Physics
1 answer:
Monica [59]2 years ago
4 0

a)You throw a stone horizontally at a speed of 5.0 m/s from the top of a cliff that is 78.4 m high.

from above statement we got

height = 78.4 m

since the ball is thrown, so its vertical velocity would be zero

u = 0

taking g = 9.8m/s^2

now, using the equation of motion

h = ut + gt^2/2

now putting all the values in it

we got ,

78.4 = 9.8 * t^2/ 2

by solving we got,

t = 4 sec

b) now, since along the horizontal , no force acting and accelaration is zero so

R = ut , R is RANGE

R = 5 * 4

range =  20 m

c)  vertical components of the stone’s velocity just before it hits the ground = v sin θ =

horizontal   components of the stone’s velocity  just before it hits the ground = v cos θ

To know more about velocity  visit :

brainly.com/question/18084516

#SPJ9

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The message refers to which of the following?
Oliga [24]

The message is the information being communicated from one place to another.

It used to be called the "intelligence".  But as time went on, it became
harder to ignore the obvious fact that that was going too far, and the
label was changed to the more IQ-neutral "message".    

7 0
3 years ago
A 96.0 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on
Ede4ka [16]

Answer:

The work done by the hoop is equal to 5.529 Joules.

Explanation:

Given that,

Mass of the hoop, m = 96 kg

The speed of the center of mass, v = 0.24 m/s

To find,

The work done by the hoop.

Solution,

The initial energy of the hoop is given by the sum of linear kinetic energy and the rotational kinetic energy. So,

K_i=\dfrac{1}{2}mv^2+\dfrac{1}{2}I\omega^2

I is the moment of inertia, I=mr^2

Since, \omega=\dfrac{v}{r}

K_i=mv^2

K_i=96\times (0.24)^2=5.529\ J

Finally it stops, so the final energy of the hoop will be, K_f=0

The work done by the hoop is equal to the change in kinetic energy as :

W=K_f-K_i

W = -5.529 Joules

So, the work done by the hoop is equal to 5.529 Joules. Therefore, this is the required solution.

4 0
3 years ago
Which of the following statements is an accurate description of sound transmission through various mediums?
yaroslaw [1]

Answer: The accurate statement which describes the transmission of sound through various medium is D.

Explanation:

Sound is longitudinal wave in which the vibration of particles travels parallel to the propagation of the motion of the wave. It requires a medium to travel. It consists of compression and rarefaction.

Sound insulator prevents the sound to travel for example plastic, wood etc. Sound travels faster in solid medium than in liquid medium. Sound travels faster in liquid than in gas. Less elastic material absorbs sound for example paper in compare to inelastic material.

Therefore, the accurate statement which describes the transmission of sound through various medium is "Sound insulators prevent sound from being transmitted better than elastic solids.

3 0
3 years ago
Read 2 more answers
A 12cm candle is placed 6cm from a converging lens with a focal length of 15cm. What is the height of the image of the candle? S
amm1812

Answer:

The height of the image of the candle is 20 cm.

Explanation:

Given that,

Size of the candle, h = 12 cm

Object distance from the candle, u = -6 cm

Focal length of converging lens, f = 15 cm

To find,

The height of the image of the candle.

Solution,

Firstly, we will find the image distance of the candle. Let it is equal to v. Using lens formula to find the image distance.

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}

v is image distance

\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-6)}\\\\v=-10\ cm

If h' is the height of the image. Magnification is given by :

m=\dfrac{h'}{h}=\dfrac{v}{u}

h'=\dfrac{vh}{u}\\\\h'=\dfrac{-10\times 12}{-6}\\\\h'=20\ cm

So, the height of the image of the candle is 20 cm.

3 0
3 years ago
A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. the flywheel has mass 40.0 kg and
tangare [24]
<span>The flywheel is solid cylindrical disc. Moment of inertial = ½ * mass * radius^2 Mass = 40.0 kg Radius = ½ * 76.0 cm = 38 cm = 0.38 meter Moment of inertial = ½ * 41 * 0.36^2 Convert rpm to radians/second The distance of 1 revolution = 1 circumference = 2 * π * r The number of radians/s in 1 revolution = 2 * π 1 minute = 60 seconds 1 revolution per minute = 2 * π radians / 60 seconds = π/30 rad/s Initial angular velocity = 500 * π/30 = 16.667 * π rad/s 170 revolutions = 170 * 2 * π = 340 * π radians The flywheel’s initial angular velocity = 16.667 * π rad/s. It decelerated at the rate of 1.071 rad/s^2 for 48.89 seconds. θ = ωi * t + ½ * α * t^2 θ = 16.667 * π * 48.89 + ½ * -1.071 * 48.89^2 2559.9 - 1280 θ = 1280 radians</span>
4 0
3 years ago
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