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myrzilka [38]
3 years ago
15

A car advertisement states that a certain car that Emily Miller love can accelerate from rest to 70km/h in 7 seconds. Fine the c

ar's average accelerate
Physics
1 answer:
alex41 [277]3 years ago
5 0

Average acceleration  =  (change in speed)  /  (time for the change)

                                       =           (70 km/hour)  /  (7 seconds)

                                       =               10  km/hr-sec .

That's a valid unit of acceleration ...  [ length / time² ] ...
but it's so clunky that we can't relate to it.  We usually
want to see acceleration in  m/s² .  So I'll convert this
answer to the more conventional unit.

                 (10 km/hr-sec) · (1,000 m / 1 km) · (1 hr / 3,600 sec)

             =  (10 · 1,000 · 1) / (1 · 3,600)  m/s²

             =          2.78  m/s²        ( about  0.28 G )
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Explanation:

There ya go !

:) hoping this helped ya out

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Una bala calibre se deja caer desde el piso 84 (a una altura de 250 metros) La bala tiene una masa de 0,008 kg. ¿A qué velocidad
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A baseball player hits a baseball with a bat. The mass of the ball is 0.25 kg. The ball accelerates at 200 m/s2. What is the for
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Read 2 more answers
A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling
ivann1987 [24]

Answer:

42.99°

Explanation:

F_h = Kinetic friction force

F_{\theta} = Pulling force at angle \theta

N_h = Weight of the box = 150 N

Kinetic friction force

F_h=\muN_h

Pulling force at angle \theta

F_{\theta}=\muN_{\theta}

N = Pulling force

According to question

\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N

Applying Newton's second law in the vertical direction we get

N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}

The angle is 42.99°

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