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eimsori [14]
3 years ago
7

Which situation is work not being done? A) A bookcase is slid across carpeting. B) A stack of books is carried at waist level ac

ross a room. C) A chair is lifted vertically with respect to the floor. D) A table is dropped onto the ground. '
Physics
1 answer:
Nastasia [14]3 years ago
5 0

Answer:

B) A stack of books is carried at waist level across a room

Explanation:

Work is defined as:

W=Fd cos \theta

where

F is the force applied

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

From the formula, we see that the work done is zero when the force and the displacement are perpendicular to each other. Let's now analyze each situation:

A) A bookcase is slid across carpeting. --> work is done, because the force that pushes the bookcase is in the same direction of the displacement

B) A stack of books is carried at waist level across a room. --> no work is done, because the force to carry the book is vertical, while the displacement of the books is horizontal

C) A chair is lifted vertically with respect to the floor. --> work is done, because the force that lifts the chair is vertical, and the displacement is vertical as well

D) A table is dropped onto the ground. --> work is done, because the force of gravity (that makes the table falling down) is vertical and the displacement of the table is also vertical.

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What is the speed of a car that travels 50m in 25min? *
ArbitrLikvidat [17]

Answer:

the speed is 2

Explanation:

speed= distance/ time

speed= 50/25

= 2

hope this helps!

4 0
2 years ago
Read 2 more answers
A frame hanging on a wall is held by two cables. The tension in each cable is 30 N, and the cables make an angle of 45° with the
Dimas [21]

Answer: option D) 42.4 N

The weight of the frame is balanced by the vertical component of tension.

W = T sin θ + T sin θ = 2 T sin θ

The tension in each cable is T = 30 N

Angle made by the cables with the horizontal, θ = 45°

⇒ W = 2×30 N × sin 45° = 2 × 30 N × 0.707 = 42.4 N

Hence, the weight of the frame is 42.4 N. Correct option is D.


6 0
3 years ago
A grain silo is shown below:grain silo formed by cylinder with radius 5 feet and height 175 feet and a half sphere on the topwha
nekit [7.7K]
Find the volume of the bottom and top separately and then add them.
Cylinder volume is the area of the bottom times the height
(22/7)(5^2)•175=13750 ft^3

The volume of a sphere is
V=(4/3)(22/7)r^3
where r is the radius. Here that's also 5 since it fits on the cylinder.
Also we only want half the sphere so use
V=(2/3)(22/7)•5^3=261.9 ft^3
Which we round upto 262.
Now add the parts together
13750+262=14,012 ft^3
6 0
3 years ago
The frequency of a microwave is 1.2 x 10^9 hertz. what is the wavelength of the given problem.
Olenka [21]

Answer:

0.25 m

Explanation:

Electromagnetic waves consist of oscillations of the electric and the magnetic field, oscillating in a plane perpendicular to the direction of motion the wave.

All electromagnetic waves travel in a vacuum always at the same speed, the speed of light, whose value is:

c=3.0\cdot 10^8 m/s

Microwave is an example of electromagnetic waves.

The relationship between wavelength and frequency for an electromagnetic wave is:

\lambda=\frac{c}{f}

where

\lambda is the wavelength

c=3.0\cdot 10^8 m/s  is the speed of light

f is the frequency

For the microwave in this problem,

f=1.2\cdot 10^9 Hz

So its wavelength is

\lambda=\frac{3.0\cdot 10^8}{1.2\cdot 10^9}=0.25 m

7 0
3 years ago
A propeller is modeled as five identical uniform rods extending radially from its axis. The length and mass of each rod are 0.77
Vikki [24]
The formula for the rotational kinetic energy is

KE_{rot} = \frac{1}{2}(number \ of\ propellers)( I)( omega)^{2}

where I is the moment of inertia. This is just mass times the square of the perpendicular distance to the axis of rotation. In other words, the radius of the propeller or this is equivalent to the length of the rod. ω is the angular velocity. We determine I and ω first.

I=m L^{2}=(2.67 \ kg) (0.777 \ m)^{2}  =2.07459 \ kgm^{2}

ω = 573 rev/min * (2π rad/rev) * (1 min/60 s) = 60 rad/s

Then,

KE_{rot} =( \frac{1}{2} )(5)(2.07459 \ kgm^{2}) (60\ rad/s)^{2}

KE_{rot} =18,671.31 \ J

6 0
3 years ago
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