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soldi70 [24.7K]
3 years ago
14

I need help in this please as soon as possible

Physics
1 answer:
topjm [15]3 years ago
7 0

Answer:

u itls

Explanation:

sorry look it up

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You are designing a rotating metal flywheel that will be used to store energy. The flywheel is to be a uniform disk with radius
Gennadij [26K]

Answer:

t = 0.0735 m

Explanation:

Angular acceleration of the flywheel is given as

\alpha = 3 rad/s^2

now after t = 8 s the speed of the flywheel is given as

\omega = \alpha t

\omega = 3 \times 8

\omega = 24 rad/s

now rotational kinetic energy of the wheel is given as

K = \frac{1}{2}I\omega^2

K = \frac{1}{2}(\frac{1}{2}mR^2)(24^2)

800 = \frac{1}{4}m(0.23)^2(24^2)

m = 105 kg

now we have

m = \rho (\pi R^2) t

105 = 8600(\pi \times 0.23^2) t

t = 0.0735 m

4 0
3 years ago
the density of dry air at 20 degrees celsius is 1.20 g/L. What is the mass of air, in kilograms, of a room that measures 24.0m b
horsena [70]
<h2>Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.</h2>

Explanation:

Density of air = 1.20 g/L = \frac{1.20\times 10^{-3}kg}{10^{-3}m^3}=1.2kg/m^3

Size of room is 24.0m by 15.0 m by 4.0 m

Volume of room = 24 x 15 x 4 = 1440 m³

We know the equation

            Mass = Volume x Density

            Mass = 1440 x 1.2

            Mass = 1728 kg  

Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.

8 0
3 years ago
You discover a binary star system in which one member is a15 solar mass main-sequence star and the other star is a 10 solar mass
Trava [24]

Answer:

yes

Explanation:

3 0
3 years ago
Find the final velocity
Verizon [17]

Answer: v = 4.4 m/s

Explanation:

In the absence of friction, the total mechanical energy will be constant

KE₀ + PE₀ = KE₁ + PE₁

0 + mg(6) = ½mv₁² + mg(5)

½mv₁² = mg(6 - 5)

v = √(2g(1)) = 4.4 m/s

3 0
3 years ago
A 60-kg runner raises his center of mass approximately 0.5 m with each step. Although his leg muscles act as a spring, recapturi
Darina [25.2K]

Answer: P = 36.75W

The additional power needed to account for the loss is 36.75W.

Explanation:

Given;

Mass of the runner m= 60 kg

Height of the centre of gravity h= 0.5m

Acceleration due to gravity g= 9.8m/s

The potential energy of the body for each step is;

P.E = mgh

P.E = 60 × 9.8 × 0.5

PE = 294J

Since the average loss per compression on the leg is 10%.

Energy loss = 10% (P.E)

E = 10% of 294J

E = 29.4J

To calculate the runner's additional power

given that time per stride is = 0.8s

Power P = Energy/time

P = E/t

P = 29.4J/0.8s

P = 36.75W

5 0
3 years ago
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