Answer:
t = 0.0735 m
Explanation:
Angular acceleration of the flywheel is given as

now after t = 8 s the speed of the flywheel is given as



now rotational kinetic energy of the wheel is given as




now we have



<h2>Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.</h2>
Explanation:
Density of air = 1.20 g/L = 
Size of room is 24.0m by 15.0 m by 4.0 m
Volume of room = 24 x 15 x 4 = 1440 m³
We know the equation
Mass = Volume x Density
Mass = 1440 x 1.2
Mass = 1728 kg
Mass of air in a room that measures 24.0 m by 15.0 m by 4.0 m is 1728 kg.
Answer: v = 4.4 m/s
Explanation:
In the absence of friction, the total mechanical energy will be constant
KE₀ + PE₀ = KE₁ + PE₁
0 + mg(6) = ½mv₁² + mg(5)
½mv₁² = mg(6 - 5)
v = √(2g(1)) = 4.4 m/s
Answer: P = 36.75W
The additional power needed to account for the loss is 36.75W.
Explanation:
Given;
Mass of the runner m= 60 kg
Height of the centre of gravity h= 0.5m
Acceleration due to gravity g= 9.8m/s
The potential energy of the body for each step is;
P.E = mgh
P.E = 60 × 9.8 × 0.5
PE = 294J
Since the average loss per compression on the leg is 10%.
Energy loss = 10% (P.E)
E = 10% of 294J
E = 29.4J
To calculate the runner's additional power
given that time per stride is = 0.8s
Power P = Energy/time
P = E/t
P = 29.4J/0.8s
P = 36.75W