To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

$\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}$

Where,

B= Magnetic Field

l = length

$\mu_0$ = Vacuum permeability

$\epsilon_0$ = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

$B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}$

Recall that the speed of light is equivalent to

$c^2 = \frac{1}{\mu_0 \epsilon_0}$

Then replacing,

$B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}$

$B = \frac{r}{2C^2} \frac{dE}{dt}$

Our values are given as

$dE = 2150N/C$

$dt = 5s$

$C = 3*10^8m/s$

$D = 0.440m \rightarrow r = 0.220m$

Replacing we have,

$B = \frac{r}{2C^2} \frac{dE}{dt}$

$B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}$

$B =5.25*10^{-16}T$

Therefore the magnetic field around this circular area is $B =5.25*10^{-16}T$

3 0

3 years ago

Witch of the following is not considered to be a greenhouse gas

nevsk [136]

None of the above, nothing is there

7 0

3 years ago

Read 2 more answers

Is the answer 0.055 seconds? (Only problem 13)

Semenov [28]

Answer:

155÷8.5

=18.235294117647

6 0

3 years ago

Which statement is not true about light? 1 point It is a particle and a wave It has mechanical and transverse waves It has mecha

belka [17]

Answer:

Option C

Explanation:

Light is an electromagnetic wave as it has characteristics of both electrical and magnetic waves. It is not a mechanical wave. Water and sound wave are mechanical wave as they need some medium to travel while light do not need any medium to travel.

Hence, option C is correct

4 0

3 years ago