The answer would be B red, violet would be the shortest
The new concentration of the solution is 0.016 M
<h3>Dilution</h3>
From the question, we are to determine the concentration of the new solution prepared from question 4.
NOTE: Question is provided below
From question 4, the concentration of the sodium chloride solution is 0.200M
Now, to determine the new concentration,
Using the dilution law
C₁V₁ = C₂V₂
Where
C₁ is the initial concentration
V₁ is the initial volume
C₂ if the final concentration
and V₂ is the final volume
Then,
C₁ = 0.200 M
V₁ = 10.00 mL
C₂ = ?
V₂ = 125.00 mL
Then,
0.200 × 10.00 = C₂ × 125.00

C₂ = 0.016 M
Hence, the new concentration of the solution is 0.016 M
Question 4:
Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution
Learn more on Dilution here: brainly.com/question/24881505
Answer:
1.50 moles
Balanced equation: 2Fe + 3Cl₂ --> 2FeCl₃
<u>find moles of iron:</u>
moles = mass/Mr
moles = 55.8/56
moles = 0.9964 moles
<u>use molar ratio:</u>
2Fe : 3Cl₂
2 : 3
moles of Cl₂ = (0.9964/2)*3 = 1.50 moles
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