Answer:
Part a)
First image
![d_i = 7.06 cm](https://tex.z-dn.net/?f=d_i%20%3D%207.06%20cm)
second image
![d_i = 13.3 cm](https://tex.z-dn.net/?f=d_i%20%3D%2013.3%20cm)
Part b)
First image
![h_i = 0.1765 cm](https://tex.z-dn.net/?f=h_i%20%3D%200.1765%20cm)
Second image
![h_i = 0.11 cm](https://tex.z-dn.net/?f=h_i%20%3D%200.11%20cm)
Explanation:
When object is placed between mirror and convex mirror
then for the first image
![d_o = 10 cm](https://tex.z-dn.net/?f=d_o%20%3D%2010%20cm)
![f = 24 cm](https://tex.z-dn.net/?f=f%20%3D%2024%20cm)
now from the mirror formula
![\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd_i%7D%20%2B%20%5Cfrac%7B1%7D%7Bd_o%7D%20%3D%20%5Cfrac%7B1%7D%7Bf%7D)
here we have
![\frac{1}{d_i} + \frac{1}{-10} = \frac{1}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd_i%7D%20%2B%20%5Cfrac%7B1%7D%7B-10%7D%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
![d_i = 7.06 cm](https://tex.z-dn.net/?f=d_i%20%3D%207.06%20cm)
For second position of image we will take object for convex mirror to be the position of image formed in plane mirror
so the distance of that image from convex mirror is
![d_o = 30 cm](https://tex.z-dn.net/?f=d_o%20%3D%2030%20cm)
now by mirror formula
![\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd_i%7D%20%2B%20%5Cfrac%7B1%7D%7Bd_o%7D%20%3D%20%5Cfrac%7B1%7D%7Bf%7D)
![\frac{1}{d_i} + \frac{1}{-30} = \frac{1}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bd_i%7D%20%2B%20%5Cfrac%7B1%7D%7B-30%7D%20%3D%20%5Cfrac%7B1%7D%7B24%7D)
![d_i = 13.3 cm](https://tex.z-dn.net/?f=d_i%20%3D%2013.3%20cm)
Part b)
Height of image and height of object is related by the equation
![h_i = \frac{d_i}{d_o} h_o](https://tex.z-dn.net/?f=h_i%20%3D%20%5Cfrac%7Bd_i%7D%7Bd_o%7D%20h_o)
![h_i = \frac{7.06}{10}(0.250)](https://tex.z-dn.net/?f=h_i%20%3D%20%5Cfrac%7B7.06%7D%7B10%7D%280.250%29)
![h_i = 0.1765 cm](https://tex.z-dn.net/?f=h_i%20%3D%200.1765%20cm)
for height of second image
![h_i = \frac{13.3}{30}(0.250)](https://tex.z-dn.net/?f=h_i%20%3D%20%5Cfrac%7B13.3%7D%7B30%7D%280.250%29)
![h_i = 0.11 cm](https://tex.z-dn.net/?f=h_i%20%3D%200.11%20cm)
The shining of the moon at night is the reflection of the sun bouncing off the surface of the moon. That is why we on Earth can see the moon appear as shining.
Answer:
convection currents is the answer
Kinetic energy<span> increases with the square of the velocity (KE=1/2*m*v^2). If the velocity is doubled, the KE quadruples. Therefore, the </span>stopping distance<span> should increase by a factor of four, assuming that the driver is </span>can<span> apply the brakes with sufficient precision to almost lock the brakes.</span>