Heat energy required to increase the temperature of water in bathtub is 12,546,000 Joules.
<h3>What is thermal energy?</h3>
The energy contained by an object by virtue of heating is known as thermal energy.
Given is the mass of water m = 150 kg, Temperature change ΔT = (40 -20)= 20 °C
The specific heat of water Cp =4182 J/kg.°C
Heat transfer Q =m x Cp x ΔT
Q = 150 x 4182 x 20
Q = 12,546,000 J
Thus, Heat energy required to increase the temperature of water in bathtub is 12,546,000 Joules.
Learn more about thermal energy.
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Answer:
A) When the baseball is rising
Explanation:
When an object like the baseball is thrown into the air, the kinetic energy is gradually converted into potential energy. When the baseball rises to its maximum height, the kinetic energy becomes zero and the kinetic energy is fully converted into potential energy.
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Answer:
- 1.3 x 10⁻¹⁵ C/m
Explanation:
Q = Total charge on the circular arc = - 353 e = - 353 (1.6 x 10⁻¹⁹) C = - 564.8 x 10⁻¹⁹ C
r = Radius of the arc = 5.30 cm = 0.053 m
θ = Angle subtended by the arc = 48° deg = 48 x 0.0175 rad = 0.84 rad (Since 1 deg = 0.0175 rad)
L = length of the arc
length of the arc is given as
L = r θ
L = (0.053) (0.84)
L = 0.045 m
λ = Linear charge density
Linear charge density is given as
Inserting the values
λ = - 1.3 x 10⁻¹⁵ C/m
Answer:
true is the answer of the question
