3 years ago

When would the temperature and thermal energy of an object differ?

1 answer:

5 0

The difference between temperature and thermal energy is that temperature measures the average kinetic speed of molecule and thermal energy is the total kinetic energy of all particles in a given substance.

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um . . . yes ?

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3 years ago

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An automobile accelerates 1.77 m/s2 over 6.00 s to reach freeway speed at the end of an

GaryK [48]

Answer:

Startinfg speed is 13.82 m/s

Explanation:

Use equation for realtion between start and final speed :

Vf=Vs+a*t

Vf-final speed

Vs-start speed

Vf=24.44m/s

a=1.77m/s²(acceleration)

t=6.00s(Time)

Vf=Vs+a*t

Vs=a*t-Vf

Vs=1.77m/s²*6s-24.44m/s

Vs=-13.82m/s

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3 years ago

A particle travels clockwise on a circular path of diameter R, monitored by a sensor on the circle at point P; the other endpo

kotykmax [81]

We make a graphic of this problem to define the angle.

The angle we can calculate through triangle relation, that is,

$sin\theta = \frac{c}{QP}\\sin\theta = \frac{c}{R}\\\theta=sin^{-1}\frac{c}{R}$

With this function we should only calculate the derivate in function of c

$\frac{d\theta}{dc} = \frac{1}{\sqrt{1-\frac{c^2}{R^2}}}(\frac{c}{R})'\\\frac{d\theta}{dc} = \frac{1}{\sqrt{R^2-c^2}}$

That is the rate of change of $\theta$ .

b) At this point we need only make a substitution of 0 for c in the equation previously found.

$\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{\sqrt{R^2-0}}\\\frac{d\theta}{dc}\big|_{c=0} = \frac{1}{R}$

Hence we have finally the rate of change when c=0.

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3 years ago

Calculate the increase in potential energy of a 60.0-kg man who climbs a ladder 10.0 meters high

andriy [413]

Potential energy = (mass) · (gravity) · (height)

PE = (60 kg) · (9.8 m/s²) · (10 m)

PE = (60 · 9.8 · 10) · (kg · m²/s² )

PE = 5,880 joules

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3 years ago

On Jupiter a rover drops a ball down a 430 m high cliff and records a fall time of 24.5 sec. what is the gravitational accelerat

Dahasolnce [82]

17.6 meters/ second squared

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4 years ago